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3 years ago

The sum of two numbers is 45. One number is 4 times and large as the other what are the numbers now

Mathematics

1 answer:

GarryVolchara [31]3 years ago

5 0

Answer:

The two numbers are 36 and 9

Step-by-step explanation:

Multiples of 4: 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48

We know that: n <44, 48

Let's try some values:

45 - 40 = 4

45- 36 = 9

45- 28 = 17

45- 24 = 21

Pattern: The lesser a natural numer's absolute value, the greater [larger number] it produces. (Bold = "larger numbers")

We recognize something: 36 + 9 = 45 and 36 is exactly 4 times greater than 9.

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Step-by-step explanation:

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After demonstrating the procedure by algebraic means, the expression $(2\sqrt[3]{12} )\cdot (3\sqrt[3]{2} )$ is equivalent to $6\cdot \sqrt[3]{24}$ .

In this question we proceed to simplify $(2\sqrt[3]{12} )\cdot (3\sqrt[3]{2} )$ by algebraic means into a single radical expression when possible, whose procedure is shown below and explained by appropriate definitions and theorems:

$(2\sqrt[3]{12} )\cdot (3\sqrt[3]{2} )$ Given.
$(2\cdot 3) \cdot (\sqrt[3]{12} \cdot \sqrt[3]{2} )$ Commutative property/ Associative property.
$6\cdot \sqrt[3]{24}$ Definition of cubic root/ $\sqrt[n]{a} = \sqrt[n]{b}$ /Result

After demonstrating the procedure by algebraic means, the expression $(2\sqrt[3]{12} )\cdot (3\sqrt[3]{2} )$ is equivalent to $6\cdot \sqrt[3]{24}$ .

To learn more on radical expressions, we kindly invite to check this verified question: brainly.com/question/1810591

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