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Vsevolod [243]
3 years ago
12

The endpoints of (MP)are M(2,1) and P(12,6). If point K partitions (MP) in a ratio of MK:KP = 3:2, what are the coordinates of K

?

Mathematics
1 answer:
GREYUIT [131]3 years ago
3 0

Answer:

K(8, 4)

Step-by-step explanation:

Given:

M(2, 1), P(12, 6)

MK:KP = 3:2

Required:

Coordinates of K

SOLUTION:

Coordinates of K can be determined using the formula below:

x = \frac{mx_2 + nx_1}{m + n}

y = \frac{my_2 + ny_1}{m + n}

Where,

M(2, 1) = (x_1, y_1)

P(12, 6) = (x_2, y_2)

m = 3, n = 2

Plug in the necessary values to find the coordinates of K:

x = \frac{mx_2 + nx_1}{m + n}

x = \frac{3(12) + 2(2)}{3 + 2}

x = \frac{36 + 4}{5}

x = \frac{40}{5}

x = 8

y = \frac{my_2 + ny_1}{m + n}

y = \frac{3(6) + 2(1)}{3 + 2}

y = \frac{18 + 2}{5}

y = \frac{20}{5}

y = 4

The coordinates of K = (8, 4)

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Trevor solved the system of equations below. What mistake did he make in his work? 2x + y = 5 x − 2y = 10 y = 5 − 2x x − 2(5 − 2
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2x+y=5 \\
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The answer is C.

Here's the correct solution:
2x+y=5 \\
x-2y=10 \\ \\
y=5-2x \\
x-2(5-2x)=10 \\
x-10+4x=10 \\
5x-10=10 \\
5x=10+10 \\
5x=20 \\
x=\frac{20}{5} \\
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y=5-2x \\
y=5 - 2 \times 4 \\
y=5-8 \\
y=-3 \\ \\
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