Answer:
0.0177
Explanation:
Cystic fibrosis is an autosomal recessive disease, thereby an individual must have both copies of the CFTR mutant alleles to have this disease. The Hardy-Weinberg equilibrium states that p² + 2pq + q² = 1, where p² represents the frequency of the homo-zygous dominant genotype (normal phenotype), q² represents the frequency of the homo-zygous recessive genotype (cystic fibrosis phenotype), and 2pq represents the frequency of the heterozygous genotype (individuals that carry one copy of the CFTR mutant allele). Moreover, under Hardy-Weinberg equilibrium, the sum of the dominant 'p' allele frequency and the recessive 'q' allele frequency is equal to 1. In this case, we can observe that the frequency of the homo-zygous recessive condition for cystic fibrosis (q²) is 1/3200. In consequence, the frequency of the recessive allele for cystic fibrosis can be calculated as follows:
1/3200 = q² (have two CFTR mutant alleles) >>  
q = √ (1/3200) = 1/56.57 >>
- Frequency of the CFTR allele q = 1/56.57 = 0.0177  
- Frequency of the dominant 'normal' allele p = 1 - q = 1 - 0.0177 = 0.9823
 
        
             
        
        
        
The correct statements are:
•An NLS can be a monopartite or bipartite signal which includes a significant number of basic amino acids.
• The recycling of importins back to their original conformation requires GTP hydrolysis in the cytoplasm.
The other answers are incorrect because GTP is not required for an importin to bind to an NLS but for the release of importin and an NES or nuclear export signal  is the sequence  in a protein for export from the cell nucleus to the cytoplasm, not to the nucleolus.
 
        
             
        
        
        
I don’t know any famous ecologists but I know their knowledge impacts us today because we wouldn’t know that much about how and why life forms interact with their habitats
        
             
        
        
        
Sex cells will always contain half of the number of chromosomes needed for a being. So if a fishes sperm cell contains 12 chromosomes and the ovum also contains 12 chromosomes then when fused together they will have 24 chromosomes in total. 
In order for the process of the fish to even be made the sperm and ovum must be fused together. Therefore the number of chromosomes that would be found in the cells forming the gills is 24 chromosomes.
        
             
        
        
        
20 Amino acids is the answer