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maks197457 [2]
3 years ago
8

An increase in herbivore populations in an ecosystem will soon lead to

Biology
2 answers:
Alexxx [7]3 years ago
8 0
And a decrease of producer populations
Angelina_Jolie [31]3 years ago
4 0
Increasing predator population
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Help plz this is so important
zhuklara [117]

Answer:

First is True, Second is False.

4 0
3 years ago
What structure holds the two sister chromatids together as they prepare for cell division.
otez555 [7]

Two sister chromatids are held together by the centromere

<h3>The Chromosome</h3>

The chromosome consists of 2 sister chromatids that are linked together by a structure known as the centromere.

Each of the sister chromatids carries an allele of the same gene.

The link between the two sister chromatids is broken at the anaphase stage of the cell division when spindle fibers pull them apart towards opposite poles within the cell.

More on the chromosome can be found here: brainly.com/question/296477

5 0
2 years ago
In a two-compartment model of a cell with a K - and Cl --permeable membrane and a 10-fold excess of KCl in the inside compartmen
Keith_Richards [23]

Answer:

When the solutions (including inside and outside) were replaced by NaCl, the membrane potential changes from a negative value of -60 mV to a positive value of + 60 mV.

Explanation:

According to the Nernst equation the potential of the membrane for a two-compartment model of a cell for positive gradient of K⁺ ions is V = - 60 mVlogK'/K where K' = inside concentration of K⁺ ions and K = outside concentration of K⁺ ions. For a 10 fold excess of KCl in the inside compartment, K'/K = 10. So,

V = - 60 mVlogK'/K = - 60 mVlog10 = -60 mV.

For a negative gradient of Na ions is V = + 60 mVlogK'/K where K' = inside concentration of Na⁺ ions and K = outside concentration of Na⁺ ions. (Since the cell is selectively permeable to Na⁺ ions. So, Na ions to not flow out but in.)For a 10 fold excess of NaCl in the inside compartment, K'/K = 10. So,

V = + 60 mVlogK'/K = + 60 mVlog10 = +60 mV.

So, when the solutions (including inside and outside) were replaced by NaCl, the membrane potential changes from a negative value of -60 mV to a positive value of + 60 mV.

8 0
3 years ago
What did Mendel's cross pollination of pea plants prove
pashok25 [27]

Answer: The correct answer is- D certain factors are dominant and other factors are recessive.

Mendel was interested in knowing the offspring that is produced from the cross pollination (that is from two different plants) as he wanted to study different traits of pea plant.

For doing so, he first removed the anthers of one plant (to prevent self pollination) and then transferred the pollens of one plant into the stigma of another plant.

When he allowed the cross pollination of purebred pea plant with other plant, he observed that some factors are dominant (such as tall height of pea plant, which masks the expression of recessive factors) and other are recessive (such as dwarf height of pea plant).

Thus, option D) is the right answer.

4 0
3 years ago
Read 2 more answers
How to determine the enzymes used to cut plasmid in cloning.
Alex73 [517]
When cloning by restriction digest and ligation, you use restriction enzymes to cut open a plasmid (backbone) and insert a linear fragment of DNA (insert) that has been cut by compatible restriction enzymes. An enzyme, DNA ligase, then covalently binds the plasmid to the new fragment thereby generating a complete, circular plasmid that can be easily maintained in a variety of biological systems. Read on for an in-depth breakdown of how to do perform restriction digests.
8 0
3 years ago
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