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kupik [55]
3 years ago
8

What is the slope of the line?

Mathematics
2 answers:
serg [7]3 years ago
4 0

Answer:

i hated iready xD the answer should be 2

Step-by-step explanation:

if you use ride over run the rise would be 2 and the run is 1 \frac{2}{1} = 2

Lerok [7]3 years ago
4 0
The answer is 2 . because if you use rise / run , the rise is 2 and the run is 1 2/1
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PLZ HELP DUE IN 1 HOUR Do you think the mean would be an appropriate measure of center to describe the data shown in the histogr
grigory [225]

Answer:

Step-by-step explanation:

the mean would be appropriate measure of center to describe the data shown in the histogram because the data is symmetrical.A symmetric histogram is a distribution in which the 2 halves appear to be the same on both sides.

3 0
3 years ago
Which polynomial function has a leading coefficient of 1 and roots /7 and - /3 with multiplicity 1?
VladimirAG [237]

Answer:

  • A.  f(x) = (x - √2)(x + √3)

Step-by-step explanation:

Leading coefficient is 1, multiplicity is 1, roots are √2 and -√3. It means the function is the product of two binomials.

<u>The function with the roots of a and b is:</u>

  • f(x) = (x - a)(x - b)

<u>Substitute and and b:</u>

  • f(x) = (x - √2)(x - (-√3)) ⇒
  • f(x) = (x - √2)(x + √3)

Correct choice is A

4 0
3 years ago
Read 2 more answers
The American Bankers Association reported that, in a sample of 120 consumer purchases in France, 48 were made with cash, compare
tatuchka [14]

Answer:

Step-by-step explanation:

Hello!

You have the information for two variables

X₁: Number of consumer purchases in France that were made with cash, in a sample of 120.

n₁= 120 consumer purchases

x₁= 48 cash purchases

p'₁= 48/120= 0.4

X₂: Number of consumer purchases in the US that were made with cash, in a sample of 55.

n₂= 55 consumer purchases

x₂= 24 cash purchases

p'₂= 24/55= 0.4364

You need to construct a 90% CI for the difference of proportions p₁-p₂

Using the central limit theorem you can approximate the distribution of both sample proportions p'₁ and p'₂ to normal, so the statistic to use to estimate the difference of proportions is an approximate standard normal:

[(p'₁-p'₂) ± Z_{1-\alpha /2} * \sqrt{\frac{p'_1(1-p'_1)}{n_1} +\frac{p'_2(1-p'_2)}{n_2} }]

Z_{0.95}= 1.648

[(0.4-0.4364)±1.648 * \sqrt{\frac{0.4(1-0.4)}{120} +\frac{0.4364(1-0.4364)}{55} }]

[-0.1689;0.0961]

The interval has a negative bond, it is ok, keep in mind that even tough proportions take values between 0 and 1, in this case, the confidence interval estimates the difference between the two proportions. It is valid for one of the bonds or the two bonds of the CI for the difference between population proportions to be negative.

I hope this helps!

8 0
3 years ago
Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 3.0 km/h due east. Runner B is initia
ArbitrLikvidat [17]

Answer:

The distance of the two runners from the flagpole is 0.0882 km

Step-by-step explanation:

We are going to use the minus sign when the runner is on the west and the plus sign when the runner is on the east.

Then, Taking into account  the runner A is 6 km west and is running with a constant velocity of 3 Km/h east, the distance of the runner A from the flagpole is given by the following equation:

Xa = -6 Km + (3 Km/h)* t

Where Xa is the position of the runner A from the flagpole and t is the time in hours.

At the same way the distance of the runner B, Xb, from the flagpole is given by the following equation:

Xb = 7.4 Km - (3.8 Km/h)*t

Then, the two runners cross their path when Xa is equal to Xb, so if we solve this equation for t, we get:

              Xa = Xb

     -6 + (3*t) =  7.4 - (3.8*t)

(3.8*t) + (3*t) = 7.4 + 6

         (6.8*t) = 13.4

                  t = 13.4/6.8

                  t = 1.9706

Therefore, at time t equal to 1.9706 hours, both runners cross their path. The distance of the two runners from the flagpole can be calculated replacing the value of t in equation for Xa or in equation for Xb as:

Xa = -6 Km + (3 Km/h)* t

Xa = -6 Km + (3 Km/h)*(1.9706 h)

Xa = -0.0882 Km

That means that both runners are 0.0882 Km west of a flagpole.

4 0
3 years ago
HELP ME PLEASE!! PLEASE
Papessa [141]
This would be the answer c
5 0
2 years ago
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