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Oxana [17]
3 years ago
8

33. What are the minimum, first quartile, median, third quartile, and maximum of the data set?

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
3 0
Given raw data: {18, 20, 11, 10, 8, 6, 12, 4} 
<span>ordered data: {4, 6, 8, 10, 11, 12, 18, 20} </span>

<span>minimum = 4 </span>
<span>maximum = 20 </span>
<span>median = (10 + 11) / 2 = 10.5 </span>
<span>first quartile is median of: {4, 6, 8, 10} or 7 </span>
<span>third quartile is median of: {11, 12, 18, 20} or 15 </span>

<span>now perform the same steps on the second set of data values </span>
<span>{60, 50, 130, 200, 180, 150, 100, 140}

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
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Scores on a final exam taken by 1200 students have a bell shaped distribution with mean=72 and standard deviation=9
SVETLANKA909090 [29]

Answer:

a. 72

b. 816

c. 570

d. 30

Step-by-step explanation:

Given the graph is a bell - shaped curve. So, we understand that this is a normal distribution and that the bell - shaped curve is a symmetric curve.

Please refer the figure for a better understanding.

a. In a normal distribution, Mean = Median = Mode

Therefore, Median = Mean = 72

b. We have to know that 68% of the values are within the first standard deviation of the mean.

i.e., 68% values are between Mean $ \pm $ Standard Deviation (SD).

Scores between 63 and 81 :

Note that 72 - 9 = 63 and

72 + 9 = 81

This implies scores between 63 and 81 constitute 68% of the values, 34% each, since the curve is symmetric.

Now, Scores between 63 and 81 = $ \frac{68}{100} \times 1200 $

= 68 X 12 = 816.

That means 816 students have scored between 63 and 81.

c. We have to know that 95% of the values lie between second Standard Deviation of the mean.

i.e., 95% values are between Mean $ \pm $ 2(SD).

Note that 90 = 72 + 2(9) = 72 + 18

Also, 54 = 63 - 18.

Scores between 54 and 90 totally constitute 95% of the values. So, Scores between 72 and 90 should amount to $ \frac{95}{2} \% $ of the values.

Therefore, Scores between 72 and 90 = $ \frac{95}{2(100)} \times 1200 = \frac{95}{200} \times 1200  $

$ \implies 95 \times 12 $ = 570.

That is a total of 570 students scored between 72 and 90.

d. We have to know that 5 % of the values lie on the thirst standard Deviation of the mean.

In this case, 5 % of the values lie between below 54 and above 90.

Since, we are asked to find scores below 54. It should be 2.5% of the values.

So, Scores below 54 = $ \frac{2.5}{100} \times 1200 $

= 2.5 X 12 = 30.

That is, 30 students have scored below 54.

8 0
3 years ago
Your friend is trying to see if you can guess the two numbers she secretly has written on her paper. Your friend tells you that
DaniilM [7]

Hello,

First we work out the equations:

x + y =62 will be the first equation.

2x= y +13 is the second equation.

We can first rewrite the second equation as 2x – y =13.

So we have:

x + y = 62

2x –y =13

KEEP IN MIND: With y being positive in one of the equations and negative in the other, we can combine the equations to quickly eliminate y and solve for x.

x + y = 62

+2x –y =13

3x = 75 divide both sides by 3 to get x.

x = 25

Now that we have x we can substitute the value for x, 25.

25 + y = 62 we can subtract 25 from both sides to get y.

y = 62- 25

y = 37

2(25) = 37 + 13

Therefore,

50 = 50

Have a amazing day.

3 0
3 years ago
the measure of one of the angles of a triangle is 35 degrees, the sum of the measures of the other two angles is 145 degrees and
kozerog [31]
80 and 65 are the measurements
7 0
3 years ago
suppose that $20,000 is invested at an interest rate of 3.2%. what would be the amount in the account in 5 years if invested
otez555 [7]

Answer:

it is D

Step-by-step explanation:

8 0
3 years ago
Thanks to everyone have a great day
pishuonlain [190]
I would think to say it is c)
4 0
3 years ago
Read 2 more answers
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