All categories

3 years ago

What is the value of the expression 18-2x(4+3)

Mathematics

1 answer:

Yanka [14]3 years ago

3 0

Answer:

12-8x

Step-by-step explanation:

18-2x(4+3) =

18 -8x -6 =

12 -8x

You might be interested in

Can someone help me :(

k0ka [10]

Answer:

x = 20

Step-by-step explanation:

19 < x < 25

x had to be higher than 19 but lower than 25

18 cant be the answer because it is less than 19

27 cant be the answer because it is higher than 25

that leaves 20, which is the right answer

19 < 20 < 25

4 0

3 years ago

Compare the two numbers using an inequality symbol square root of 25 and square root of 64

Gnoma [55]

The square root of 64 is greater than the square root of 25; (square root sign) 64 > (square root sign) 25

4 0

3 years ago

What is the mode of the data? A) 9 B) 12 C)26 D) 35

Flauer [41]

Answer:

c)26 or positive and negative

5 0

3 years ago

MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t

ioda

Answer:

We would have

$l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}$

where " l " is length, " w" is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

Surface area for a box with no top = $lw+2lh+2wh = 64$

where " l " is length, " w" is width and "h" is height.

Step 2.

Remember as well that

Volume of the box = $l*w*h$

Step 3

We can now use lagrange multipliers. Lets say,

$F(l,w,h) = lwh$

and

$g(l,w,h) = lw+2lh+2wh = 64$

By the lagrange multipliers method we know that

$\nabla F = \lambda \nabla g$

Step 4

Remember that

$\nabla F = (wh,lh,lw)$

and

$\nabla g = (w+2h,l+2h , 2w+2l)$

So basically you will have the system of equations

$wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)$

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

$lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)$

Then you would get

$l\lambda (w+2h) = w\lambda (l+2h) = h\lambda (2w+2l)$

You can get rid of $\lambda$ from these equations and you would get

$lw+2lh = lw+2wh = 2wh+2lh$

And from those equations you would get

$l = w =2h$

Now remember the original equation

$lw+2lh+2wh = 64$

If we plug in what we just got, we would have

$l^{2} + l^{2} + l^2 = 64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}$

7 0

3 years ago

Which of the following equations is the result of completing the square on x^2 - 6x - 9 = 0?

lina2011 [118]

X² - 6x - 9 = 0
x² - 3x - 3x - 9 = 0
x (x-3) -3(x + 3) = 0
(x - 3)² = 0

In short, Your Answer would be Option A

Hope this helps!

6 0

3 years ago

Read 2 more answers