Answer:
first ones 11
Step-by-step explanation:
-22/-2=11
Answer:
x = 43
Step-by-step explanation:
x = 98 - 55
<u>x = 43</u>
Average=(total number)/(number of items)
given that the final exam counts as two test, let the final exam be x. The weight of the final exams on the average is 2, thus the final exam can be written as 2x because any score Shureka gets will be doubled before the averaging.
Hence our inequality will be as follows:
(67+68+76+63+2x)/6≥71
(274+2x)/6≥71
solving the above we get:
274+2x≥71×6
274+2x≥426
2x≥426-274
2x≥152
x≥76
b] The above answer is x≥76, the mean of this is that if Shureka is aiming at getting an average of 71 or above, then she should be able to get a minimum score of 76 or above. Anything less than 76 will drop her average lower than 71.
234 - 3 = 231
231 : 3 = 77
77 + 1 =78
78 + 1 = 79
------------------------
77 78 79
77+78+79= 234
Answer:
Well just looking at the choices can lead you to the answer right away.
Well since the probability of boys and girls are equal, its 50/50. And since 125 in half well about is about 60-62 and the minimum amount of girls has to be 70. It can’t be higher then half and the choices remain to less then half not including 50%. So that eliminates all 3 choices except B.
