The answer would be 70 degrees.
In order to find this answer, we must first look at the cos value of an angle. The unknown angle here gives us an adjacent side of 3.4 and a hypotenuse of 10. Thus, we can use the following with cos.
Cos(A) = 3.4/10 or Cos(A) = .34
As a result, we can then use the arccos function to find the answer.
acrcos(.34) = A
70.12 = A
Then when we round, we'd get 70.
9514 1404 393
Answer:
779.4 square units
Step-by-step explanation:
You seem to have several problems of this type, so we'll derive a formula for the area of an n-gon of radius r.
One central triangle will have a central angle of α = 360°/n. For example, a hexagon has a central angle of α = 360°/6 = 60°. The area of that central triangle is given by the formula ...
A = (1/2)r²sin(α)
Since there are n such triangles, the area of the n-gon is ...
A = (n/2)r²sin(360°/n)
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For a hexagon (n=6) with radius 10√3, the area is ...
A = (6/2)(10√3)²sin(360°/6) = 450√3 ≈ 779.4 . . . . square units
Answer:
x = 3.4
Step-by-step explanation:
Given the graphs of 2 functions, then the solutions to both are at their points of intersection, that is
where f(x) = g(x)
There are 3 possible points of intersection to f(x) = g(x)
The one on the list , however, is at x = 3.4
Answer:
V=1
4h﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4
Step-by-step explanation:
