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SCORPION-xisa [38]
2 years ago
10

Please help me, i don’t know how to do this:)

Mathematics
1 answer:
Reil [10]2 years ago
4 0

x=12, y=6\sqrt{2}

This triangle is a special right triangle, a 45-45-90 triangle. In this format, the the hypotenuse will be x\sqrt{2}, while the side lengths would be x. With this in mind we can already figure out y is 6\sqrt{2}. The hypotenuse would be (6\sqrt{2} )(\sqrt{2} )=12

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5.4.

Step-by-step explanation:

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When AB=3x+8 and GJ=2x+24 what is AB?
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Six more than the quotient of a number and 2 equals 8
ikadub [295]
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Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.
Romashka [77]
By definition, the average change of rate is given by:
 AVR =  \frac{f(x2)-f(x1)}{x2-x1}
 We will calculate AVR for each of the functions.
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f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18
 AVR = \frac{-2-18}{-2-3}
 AVR = \frac{-20}{-5}
 AVR = 4

 f(x) = 3x - 8 interval: [4, 5]:
 f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7
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 AVR = \frac{3}{1}
 AVR = 3

 f(x) = x^2 - 2x interval: [-3, 4]
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f(4) = (4)^2 - 2(4) = 16 - 8 = 8
 AVR = \frac{8-15}{4+3}
 AVR = \frac{-7}{7}
 AVR = -1

 f(x) = x^2 - 5 interval: [-1, 1]
 f(-1) = (-1)^2 - 5 = 1 - 5 = -4

f(1) = (1)^2 - 5 = 1 - 5 = -4
 AVR = \frac{-4+4}{1+1}
 AVR = \frac{0}{2}
 AVR = 0


 Answer:
 
these functions from the greatest to the least value based on the average rate of change are:
 f(x) = x^2 + 3x
 
f(x) = 3x - 8
 
f(x) = x^2 - 5
 
f(x) = x^2 - 2x
5 0
3 years ago
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