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Bad White [126]
3 years ago
11

Order the numbers from least to greatest. 161, 101, 1-91, 1 – 4.2||

Mathematics
1 answer:
Yanka [14]3 years ago
4 0

Answer: 1-91,1-42,101,161

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Kim is a medical supplies salesperson. Each month she receives a 5% commission on all her sales of medical supplies up to $20,00
lions [1.4K]

Answer: her sales for the month of May is $55000

Step-by-step explanation:

Let x represent her total sales for the month of May.

Each month she receives a 5% commission on all her sales of medical supplies up to $20,000. This means that for her first sales worth $20000, she earns a commission of

5/100 × 20000 = 1000

She also earns 8.5% on her total sales over $20,000. This means that for sales over $20000, she earns

8.5/100(x - 20000) = 0.085x - 1700

Her total commission for May was $3,975. The expression becomes

1000 + 0.085x - 1700 = 3975

0.085x = 3975 + 1700 - 1000

0.085x = 4675

x = 4675/0.085

x = 55000

5 0
3 years ago
The time needed to complete a final examination in a particular college course is normallydistributed with a mean of 80 minutes
Artist 52 [7]

Answer:

a) 0.023

b) 0.286

c) 10 students will be unable to complete the exam inthe allotted time.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 80 minutes

Standard Deviation, σ = 10 minutes

We are given that the distribution of time to complete an exam is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(completing the exam in one hour or less)

P(x < 60)

P( x < 60) = P( z < \displaystyle\frac{60 - 80}{10}) = P(z < -2)

Calculation the value from standard normal z table, we have,  

P(x < 60) =0.023= 2.3\%

b) P(complete the exam in more than 60 minutes but less than 75 minutes)

P(60 \leq x \leq 75) = P(\displaystyle\frac{60 - 80}{10} \leq z \leq \displaystyle\frac{75-80}{10}) = P(-2 \leq z \leq -0.5)\\\\= P(z \leq -0.5) - P(z < -2)\\= 0.309- 0.023 = 0.286= 28.6\%

c) P(completing the exam in more than 90 minutes)

P(x > 90)

P( x > 90) = P( z > \displaystyle\frac{90 -80}{10}) = P(z > 1)

= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,  

P(x > 90) = 1 - 0.8413 = 0.1587 = 15.87\%

15.87% of children of class will require more than 90 minutes to complete the test.

Number of children =

\dfrac{15.87}{100}\times 60 = 9.52\approx 10

Approximately, 10 students of class will require more than 90 minutes to complete the test.

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4 years ago
WHATs 2 PLUS 2 plus 345555 minus 234 times 454
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Answer:

This can be solved using a calculator

239323

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