Step-by-step explanation:
We have:
x - y = 43 , xy = 15
To find, the value of x^2+y^2x
2
+y
2
= ?
∴ x - y = 43
Squaring both sides, we get
(x - y)^2(x−y)
2
= 43^243
2
⇒ x^2+y^2x
2
+y
2
- 2xy = 1849
Using the algebraic identity,
(a - b)^2(a−b)
2
= a^2+b^2a
2
+b
2
- 2ab
⇒ x^2+y^2x
2
+y
2
= 1849 + 2xy
Put xy = 15, we get
x^2+y^2x
2
+y
2
= 1849 + 2(15)
⇒ x^2+y^2x
2
+y
2
= 1849 + 30
⇒ x^2+y^2x
2
+y
2
= 1879
∴ x^2+y^2x
2
+y
2
= 1879
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6^9 x 6^-7 = 6^2
x= -7
Hope this helps :)
Answer: Here you go
..........................................
Answer:
x = 10
Step-by-step explanation:
=> 4x + 1 + 2x = 61
=> 6x = 61 - 1
=> 6x = 60
=> x = 60/6
=> x = 10
<u>Hence</u><u> </u><u>the</u><u> value</u><u> of</u><u> x</u><u> </u><u>is</u><u> </u><u>1</u><u>0</u><u> </u><u>.</u>
