Question

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!

Answer 1

Answer: $tan(E)=1.70$

Step-by-step explanation:

For this exercise you need to remember the following Trigonometric Identity:

$tan\alpha =\frac{opposite}{adjacent}$

You must observe the figure given in the exercise.

You can notice that the given triangle EFG is a Right triangle (Right triangles are defined as those triangles that have an angle that measures 90 degrees).

So, you can identify in the figure that:

$\alpha=E\\\\ opposite=FG=56\\\\adjacent=EF=33$

So, knowing these values, you can substitute them into  $tan\alpha =\frac{opposite}{adjacent}$ and then you must evaluate (Remember to round the result to the nearest hundreth).

Therefore, through this procedure you get:

 $tan(E)=\frac{56}{33}\\\\tan(E)=1.70$