3 years ago

The diagonals of a kite are 22 feet and 33 long. what is the area ?

Mathematics

1 answer:

Goshia [24]3 years ago

7 0

Answer:

A=363

Step-by-step explanation:

To solve the area of a kite you use

$a = \frac{pq}{2}$

So 22×33=726 then divide that by 2 and you get 363.

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What is the area of this rectangle?

I am Lyosha [343]

The area of the rectangle would be 44 this is because area is Length x Width so the very top of the rectangle is 4 cm and going up on the side is 11 so 4x11 is 44 which is ur area.

Hope this helps!

3 0

3 years ago

The sample consisted of 50 night students, with a sample mean GPA of 3.02 and a standard deviation of 0.08, and 25 day students,

bulgar [2K]

Answer: The test statistic is t= -0.90.

Step-by-step explanation:

Since we have given that

n₁ = 50

n₂ = 25

$\bar{x_1}=3.02\\\\\bar{x_2}=3.04\\\\\sigma_1=0.08\\\\\sigma_2=0.06$

So, s would be

$s=\sqrt{\dfrac{n_1\sigma_1^2+n_2\sigma_2^2}{n_1+n_2-2}}\\\\s=\sqrt{\dfrac{50\times 0.08^2+25\times 0.06^2}{50+25-2}}\\\\s=0.075$

So, the value of test statistic would be

$t=\dfrac{\bar{x_1}-\bar{x_2}}{s(\dfrac{1}{n_1}+\dfrac{1}{n_2})}\\t=\dfrac{3.02-3.04}{0.074(\dfrac{1}{50}+\dfrac{1}{25})}\\\\t=\dfrac{-0.04}{0.074(0.02+0.04)}\\\\t=\dfrac{-0.04}{0.044}\\\\t=-0.90$