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2 years ago

Pls help “What transformations of f(x)=x^2 would yield g(x)=(x-E)^2-A?

Mathematics

1 answer:

Ivan2 years ago

4 0

right E units, down A units

whenever you have ( -E) whatever you have Inside you do the opposite just like this problem. We have -E so to the right. if it was positive we go left

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Can someone help with math?

algol [13]

Answer:

A. {4,3}

Step-by-step explanation:

x -2y = -2

y = - 3x +15

x - 2(-3x+15) = -2

x +6x - 30 = -2

7x = 28

x = 4

y = - 3x +15 = - 3*4 + 15 = -12 + 15 = 3

{4,3}

5 0

3 years ago

Which expression is equivalnt (-18) - 64n

Naily [24]

Answer:

Your correct answer is option C. -2 (9 + 32n)

Step-by-step explanation:

Solution:

Options are not given in the question

Given First degree expression:

-18-64n

= (-2)×9 + (-2)×32n

Take (-2) common, we get

= (-2)( 9+32n)

Therefore you get your answer of option C. -2(9+32n)

8 0

3 years ago

Read 2 more answers

Can I get help with finding the Fourier cosine series of F(x) = x - x^2

trapecia [35]

Assuming you want the cosine series expansion over an arbitrary symmetric interval $[-L,L]$ , $L\neq0$ , the cosine series is given by

$f_C(x)=\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos nx$

You have

$a_0=\displaystyle\frac1L\int_{-L}^Lf(x)\,\mathrm dx$
$a_0=\dfrac1L\left(\dfrac{x^2}2-\dfrac{x^3}3\right)\bigg|_{x=-L}^{x=L}$
$a_0=\dfrac1L\left(\left(\dfrac{L^2}2-\dfrac{L^3}3\right)-\left(\dfrac{(-L)^2}2-\dfrac{(-L)^3}3\right)\right)$
$a_0=-\dfrac{2L^2}3$

$a_n=\displaystyle\frac1L\int_{-L}^Lf(x)\cos nx\,\mathrm dx$

Two successive rounds of integration by parts (I leave the details to you) gives an antiderivative of

$\displaystyle\int(x-x^2)\cos nx\,\mathrm dx=\frac{(1-2x)\cos nx}{n^2}-\dfrac{(2+n^2x-n^2x^2)\sin nx}{n^3}$

and so

$a_n=-\dfrac{4L\cos nL}{n^2}+\dfrac{(4-2n^2L^2)\sin nL}{n^3}$

So the cosine series for $f(x)$ periodic over an interval $[-L,L]$ is

$f_C(x)=-\dfrac{L^2}3+\displaystyle\sum_{n\ge1}\left(-\dfrac{4L\cos nL}{n^2L}+\dfrac{(4-2n^2L^2)\sin nL}{n^3L}\right)\cos nx$

4 0

3 years ago

Y varies inversely with x, y = 4 and x = 3, what is y, when x = 2B) given: y = 2x - 1 (x-3)(x+1) what is the I. VAII. HA III. X-

Semmy [17]

SOLUTION

(a)

$\begin{gathered} y\alpha\frac{1}{x} \\ \\ y=\frac{k}{x} \\ \\ 4=\frac{k}{3} \\ \\ k=12 \end{gathered}$ $\begin{gathered} y=\frac{12}{x} \\ \\ when\text{ x=2} \\ \\ y=\frac{12}{2} \\ \\ y=6 \end{gathered}$

4 0

1 year ago

A trapezoid has a height of 10xy centimeters. It's shorter base is 15y centimeters, and it's longer base is 26y centimeters. Use

Zina [86]

Answer:

1233

Step-by-step explanation:

3 0

3 years ago