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Solnce55 [7]
3 years ago
9

Will give brainliest!! please help me!!

Mathematics
1 answer:
erik [133]3 years ago
6 0

Answer:

D

Step-by-step explanation:

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2/3 of 16 <br><br><br><br><br><br> ...........................
maxonik [38]

Answer:

2/3 * 16

32/3 = 10.66

hope it helps

5 0
3 years ago
Read 2 more answers
Which property does the equation illustrate?<br> 0 +-b= -b?
konstantin123 [22]

Answer:

The property the equation illustrates would be the zero property of addition.

Step-by-step explanation:

The additive property of zero states that when you have any number and add zero to it, your answer will always equal the original number.

8 0
3 years ago
D) If C.P. - Rs 100, S.P. Rs 80, then loss percent​
AfilCa [17]

Step-by-step explanation:

Selling price = Rs.80

Cost price = Rs.100

here, CP > SP

Now...

Loss ( L ) = CP - SP

= RS.100 - 80

= Rs.20

Now...

loss \: percent \:  =  \frac{loss}{CP}  \times 100%

=  \frac{2000}{100}  \\

= 20 %

3 0
2 years ago
Two parallel lines are _____ coplanar.
dimulka [17.4K]

Answer:

1. always

2. sometimes

Step-by-step explanation:

Two lines are coplanar if they lie in the same plane or in parallel planes. There is  ALWAYS a plane which contains two parallel lines (see first attached image for details).

Two lines that lie in parallel planes are sometimes parallel. For example, see at second image. Planes \alpha and \beta are parallel. Consider pair of lines a and a_1 - they are parallel, but if you consider the pair of lines a and b_1, you can see they are not parallel.

8 0
3 years ago
Read 2 more answers
ABCD is a trapezoid.<br> What is the area of trapezoid?
lana [24]
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
  Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
  Area = (1/2)(AB + AB/4)·h = (5/8)AB·h

The given dimensions let us determine the area of ∆BCE to be
  Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²

The total area of the trapezoid is also the sum of the areas ...
  Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
  Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
  Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h

Putting all of the above into the equation for the total area of the trapezoid, we have
  Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
  (5/8 -1/6 -1/12)AB·h = 30 cm²
  AB·h = (30 cm²)/(3/8) = 80 cm²

Then the area of the trapezoid is
  Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
6 0
3 years ago
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