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Lina20 [59]
3 years ago
6

2 1/3 divided by y= -1.27272727 what does y equal

Mathematics
1 answer:
Semmy [17]3 years ago
6 0

Answer:

-1.83337261989

Step-by-step explanation:

(2 1/3)/y=-1.272727

2 1/3 = -1.272727y

y=-1.83337261989

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Find the critical value t for the confidence level c= 0.98 and sample size n=7.
kenny6666 [7]

Answer:

The critical value is T = 3.143.

Step-by-step explanation:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 7 - 1 = 6

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 6 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.98}{2} = 0.99. So we have T = 3.143.

The critical value is T = 3.143.

8 0
3 years ago
Find the slope and y-intercept of equation y= 10x + 18
pickupchik [31]

Answer:

slope is 10

y-intercept is 18

Step-by-step explanation:

3 0
2 years ago
You flip a coin three times in a row. What is the probability you will get three tails?
Romashka-Z-Leto [24]

Answer:

50/50

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
X = A 21.6 B 12.9 C 9.1
Artist 52 [7]

Answer:

B: 12.9

Step-by-step explanation:

If A B and C are the alternatives, the answer is B: 12.9

The reason is that the hypotenuse can't be smaller than one of its sides, that eliminates alternative C.

And also, the hypotenuse can't be bigger than segments AC + BC, since the side AC is bigger and AC measures 10.8, the hypotenuse would have to measure < 21.6

Any questions, comment.

6 0
3 years ago
Read 2 more answers
true or false If x represents a random variable with mean 114 and standard deviation 40, then the standard deviation of the samp
Goshia [24]

Answer:

\mu = 114, \sigma = 40

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard deviation for the sampling distribution would be:

\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4

So then the answer is TRUE

Step-by-step explanation:

Let X the random variable of interest and we know that the true mean and deviation for this case are given by:

\mu = 114, \sigma = 40

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard deviation for the sampling distribution would be:

\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4

So then the answer is TRUE

6 0
3 years ago
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