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3 years ago

What is factoring? Why is it important?

Mathematics

2 answers:

mel-nik [20]3 years ago

4 0

Because it specialises the groups that go into the number.

Black_prince [1.1K]3 years ago

3 0

Factoring allows us to solve things and helps break down numbers

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Someone help with this math question please!!

Reptile [31]

In rectangle : US=RT
2SO=US
6x+4=14x-12
X=16/8
6(16/8)+4=your answer

6 0

3 years ago

Circle A has an area of 452.16ft2. With a radius of 12 ft. If circle B has a radius of 17 ft, what is it’s area?

ehidna [41]

Answer: 907.92 ft²

Step-by-step explanation:

1. To solve this problem you must apply the formula for calculate the area of a circle, which is shown below:

$A=r^{2}\pi$

Where r is the radius of the circle.

2. You know the radius of the circle B, therefore, when you susbtitute it into the formula, you obtain that the area of the circle B is:

$A_B=(17ft)^{2}\pi=907.92ft^{2}$

7 0

3 years ago

Read 2 more answers

Determine whether a tangent line is shown in this figure? a. no b. yes

faust18 [17]

No, the tangent line needs to be against the circle from where it leaves. This is just a straight up right angle.

7 0

3 years ago

Read 2 more answers

When 7 is subtracted from two third of the square of a number it becomes 17 find the number

Dmitry [639]

Answer: 6 or -6

hello,

Step-by-step explanation:

Let say n the number

$\dfrac{2}{3} *n^2-7=17\\\Longrightarrow\ \dfrac{2}{3} *n^2=24\\\Longrightarrow\ n^2=\dfrac{3*24}{2}\\\Longrightarrow\ n^2=36\\\Longrightarrow\ (n-6)(n+6)=0\\\\n=6\ or\ n=-6\\$

8 0

2 years ago

What is the answer and how do you solve 21x^3/3x^−1

Sunny_sXe [5.5K]

Answer:

as written: 7x^2

perhaps intended: 7x^4

Step-by-step explanation:

As written, the Order of Operations specifies that the only denominator factor is 3, so the expression is interpreted as ...

$\dfrac{21x^3}{3}x^{-1}=\dfrac{21}{3}x^{3-1}=7x^2$

___

Sometimes grouping of denominator factors is intended, but parentheses are not written as they should be. If the intention is ...

21x^3/(3x^-1)

then the simplification is ...

$\dfrac{21x^3}{3x^{-1}}=\dfrac{21}{3}x^{3-(-1)}=7x^4$

_____

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

a^b/a^c = a^(b-c)

6 0

3 years ago