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olganol [36]
3 years ago
6

Franklin deposits $3500 in an account that earns 3.5% interest compounded annually. Which function equation represents the balan

ce of the account after t years?
f(t)=3500(0.035)t

f(t)=3500(3.5)t

f(t)=3500(1.035)t

f(t)=3500(1.35)t
Mathematics
2 answers:
Effectus [21]3 years ago
8 0

Answer:

f(t)=3500(1.035)t



Nikolay [14]3 years ago
6 0
Hello! 3.5% in decimal form is 0.035. You add 1 to that to get 1.035. B is out, because that number is too high. A is out, because it doesn't add 1. The formula for compound interest is P(1 + r)^t. D is also out, because it incorrectly interprets 3.5% in decimal form. The correct form is 3,500(1.035)^t. The only one that shows this is C.  Therefore, the answer is C.
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An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from so
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Solution :

Let p_1 and p_2  represents the proportions of the seeds which germinate among the seeds planted in the soil containing 3\% and 5\% mushroom compost by weight respectively.

To test the null hypothesis H_0: p_1=p_2 against the alternate hypothesis  H_1:p_1 \neq p_2 .

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The test statistic can be written as :

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which under H_0  follows the standard normal distribution.

We reject H_0 at 0.05 level of significance, if the P-value or if |z_{obs}|>Z_{0.025}

Now, the value of the test statistics = -1.368928

The critical value = \pm 1.959964

P-value = $P(|z|> z_{obs})= 2 \times P(z< -1.367928)$

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Since the p-value > 0.05 and $|z_{obs}| \ngtr z_{critical} = 1.959964$, so we fail to reject H_0 at 0.05 level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the \text{proportion} of the seeds that \text{germinate differs} with the percent of the \text{mushroom compost} in the soil.

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