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navik [9.2K]
2 years ago
15

∫ ⊃øℕτ ωΛℕℕΛ βΣ ℏΣℝΣ βℝ∪ℏ

Mathematics
1 answer:
frutty [35]2 years ago
4 0

Answer:

same

Step-by-step explanation:

heheh

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Set up and solve the following using dimensional analysis.
Softa [21]
1).  Multiply (5400 inches) by (1 foot / 12 inch) then by (1 mile / 5280 foot).

      (See explanation at the bottom)

         =      (5400 inch) x (1 foot / 12 inch) x (1 mile / 5280 foot)

         =      (5400 x 1 x 1 / 12 x 5280)  (inch - foot - mile / inch - foot) 

         =          0.0852  mile  


2).  Multiply (16 week) by (7 day/week) then by (24 hour/day)
       then by (60 minute/hour) then by (60 sec/minute).

3).  Multiply (54 yards) by (3 foot/yard) then by (1 meter/3.28 foot)
       and then by (1000 mm/meter)

4).  Multiply (36 cm/second) by (3600 second/hour) then by (1 meter/100 cm)
      then by (1 mile/1609.3 meter).

5).  Look up how many grams in a pound  ('P')
       Look up how many mL in a gallon       ('G')

      Multiply (1.09 g/mL) by ( 1 pound/ P gram) then by (1 gallon/ G mL)

6).  Multiply (32 foot/sec) by (1 meter / 3.28 foot) then by (60 sec/minute).


Each time I told you to multiply by something, it was always a fraction
where the numerator and denominator are equal, like (60 seconds/minute)
or (1 foot / 12 inch).  Since the top and bottom of the fraction are equal, the
value of the fraction is ' 1 ' , and multiplying by it doesn't change the value,
it only changes the units ... that's what this whole exercise is about.
When you multiply, KEEP the units in the product, and then, after you multiply, you can 'cancel' units out of the top and bottom of the product.
Like if you have 'feet' on top and bottom, just cross them out.  When you're done, if you did it correctly, the last unit you end up with will be the one you want.      
4 0
3 years ago
This person did something wrong and I do not know what it is :( Please help this is for points!
Inga [223]

Answer:

It is, indeed, a reduction. But, the scale factor of the dilation should be a fraction instead of a whole number, since the shape has shrunk.

Instead of \frac{KN}{K'N'}, it should be \frac{K'N'}{KN}. That would make it (4 - 2) / (8 - 4) = 2 / 4 = 1/2.

Hope this helps!

7 0
3 years ago
Solve the equation using the quadratic formula
amm1812

Answer:

Step-by-step explanation:

Rewrite this quadratic equation in standard form:  2n^2 + 3n + 54 = 0.  Identify the coefficients of the n terms:  they are 2, 3, 54.

Find the discriminant b^2 - 4ac:  It is 3^2 - 4(2)(54), or -423.  The negative sign tells us that this quadratic has two unequal, complex roots, which are:

     -(3) ± i√423        -3 ± i√423

n = ------------------- = ------------------

             2(2)                      4

3 0
2 years ago
Crisps <br> normal price £1.43 <br> three for the price of two<br> what is the total of 6 packets
Anettt [7]

Answer:

3 packs equal the price of two, therefore 1.43•2= 2.86

and 6 packs equal the price of 4, so 2.86•2= 5.72

7 0
2 years ago
The bids in an online auction are represented by the arithmetic sequence shown below. Write an explicit formula to represent the
zmey [24]

(a) The nth term of the sequence is given by A(n)=195 + (n - 1)10.

(b) The 12th term of the sequence is A(12) = 305.

<h3>What is an arithmetic sequence?</h3>

One arithmetic progression with a common difference of 2 is the sequence 5, 7, 9, 11, 13, 15,...

The term "finite arithmetic progression" or "arithmetic progression" refers to a limited segment of an arithmetic progression.

A mathematical sequence has the following structure: a, a+d, a+2d, a+3d, etc., up to n terms. The initial term is a, the shared distinction is d, and n is the total number of words. Find the AP, the first term, the number of terms, and the common difference for the computation using the arithmetic sequence formulae. To determine the nth term, sum, or common difference of a given arithmetic sequence, many formulae related to arithmetic series are utilized.

A(n)=195+(n-1)10

The given arithmetic sequence is 195, 205, 215, 225,.....

The first term a =195

The common difference d= 205-195

d =215-205

d =225-215

So, d = 10

(a) The nth term is given by

A(n)=a+(n-1)d

A(n)=195+(n-1)10

(b) For n=12, the 12th term is given by

A(12)=195+11(10)

A(12)=305

Therefore, A(n)=195+(n-1)10

And A(12)=305

To know more about the arithmetic sequences, visit:

brainly.com/question/15412619

#SPJ1

8 0
1 year ago
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