Triangles JFE and JLK are similar provided that line segments FE and LK are parallel. This means that corresponding parts of these triangles occur proportionally to one another. In particular,

From this relation we get

Now we can solve for
:




Answer: 1) y>-11
Step-by-step explanation:
Divide both sides by q, E=F/q
If 200 percent is 11 then 100 is 11/2 which is exactly 5.5.