After calculating the stock and savings account total I found out that the difference in earning between them is $104.738.
Answer:
0.1994 is the required probability.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 166 pounds
Standard Deviation, σ = 5.3 pounds
Sample size, n = 20
We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.
Formula:
Standard error due to sampling =

P(sample of 20 boxers is more than 167 pounds)
Calculation the value from standard normal z table, we have,
0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds
Answer:
can I get a hiaaa
How was the government able to make children go to residential school?
Let's call the aces
for hearts, diamonds, clubs and spades. So,
are red and [ted] c, s[/tex] are black.
Since the first card is replaced, the two picks are identical. This means that the sample space is given by all the possible couple

There are 16 such couples (we have four choices for the first card, and the same four choices for the second card). Now let's compute the odds in our favour to deduce the probability of winning:
If we want a player to draw two card of the same colour, the following couples are good:

so 8 possible couples over 16. This means that the probability that a player draws two cards of the same color is 8/16 = 1/2.
Similarly, the probability of drawing a red ace first and then a black ace is represented by the following couples:

which are 4 over the same 16 as above, thus leading to a probability of 4/16 = 1/4.
To find this, just plug the numbers into the expressions.
5x = y
5(2) = 7
10 = 7
So it can't be A.
x + 2 = y
2 + 2 = 7
4 = 7
x + 4 = y
2 + 4 = 7
6 = 7
2x + 3 = y
2(2) + 3 = 7
7 = 7
The correct answer is
D. 2x + 3