Answer:
The length of AC is 222 units.
Step-by-step explanation:
Given AC and AE are common external tangents of G and D.
BC= 123 , GB=20 and AG=101.
We have to find the measure of AC.
As, a straight line joined from the center i.e radius is perpendicular to tangent drawn. Therefore,
In ΔABG, by Pythagoras theorem
⇒
⇒
⇒ AB=99 units.
Hence, AC=AB+BC=99+123=222 units.
The length of AC is 222 units.
the length of the side of this square is cm
Answer:
Solutions Given:
let diagonal of square be AC: 8 cm
let each side be a.
As diagonal bisect square.
let it forms right angled triangle ABC .
Where diagonal AC is hypotenuse and a is their opposite side and base.
By using Pythagoras law
hypotenuse ²=opposite side²+base side²
8²=a²+a²
64=2a²
a²=
a²=32
doing square root on both side
a=±
a=±2*2
Since side of square is always positive so
a=4 or 5.65 cm
Answer:
6x - 11y = -13 is the answer.
Step-by-step explanation:
Let's plug in the points to see what sticks.
Start with (-4, -1)
1) 11x - 6y = 11(-4) - 6(-1) = -44 + 6 = -38 13
2) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13
3) 6x - 7y = 6(-4) - 7(-1) = -24 + 7 = -17 17
4) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13 13
The only one that fits is #2. Let's try the other point to be sure.
2) 6x - 11y = 6(1.5) - 11(2) = 9 - 22 = -13
Answer:
Step-by-step explanation:
we know that
In a parallelogram the diagonals bisect each other
The figure XYZW is a parallelogram
so
VW=VY
VX=VZ
<em>Find the value of b</em>
VW=VY
substitute the given values
solve for b
Find the length of YW
----> by addition segment postulate
substitute the value of b