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Rom4ik [11]
3 years ago
9

Each marble bag sold by Hans's Marble Company contains 8 purple marbles for every 5 green marbles. If a bag has 30 green marbles

, how many purple marbles does it contain?
Mathematics
1 answer:
gregori [183]3 years ago
3 0

We can set up a proportion since we know the ratio between the # of purple marbles and the # of green marbles.

A ratio is a way to compare two different values: for every 8 purple marbles there are 5 green marbles

<h2>\frac{8}{5} = \frac{p}{30}</h2><h2 /><h2>when we cross multiply, we get 5p = 240 </h2><h2>we divide both sides by 5 to isolate the variable </h2><h2 /><h3><u>There are 48 purple marbles </u></h3>
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Answer:

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Step-by-step explanation:

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

H0: p = 0.11

This means that 0.11 is tested at the null hypothesis, and so:

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The engineer weighs 94 bags and finds that 16 of them are over-filled.

This means that:

n = 94, X = \frac{16}{94} = 0.1702

What is the test statistic?

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.1702 - 0.11}{\frac{0.3129}{\sqrt{94}}}

z = 1.865

The test statistic is z = 1.865.

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3 years ago
After creating a hypothesis, Janis decides how to best measure the impact of her manipulation. This variable that is impacted by
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Answer:

This variable that is impacted by manipulating the independent variable is known as dependent variable

Step-by-step explanation:

One of the methods to test a hypothesis is the use of independent variable. The independent variable is manipulated to know if the change will be effective or not.

The variable which will be impacted by the independent variable is called dependent variable. The researcher manipulated the values for independent variable to check if the dependent variable changes or not ..

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Step-by-step explanation:

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3 years ago
An instructor who taught two sections of Math 161A, the first with 20 students and the second with 30 students, gave a midterm e
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Answer:

<em>The answers are for option (a) 0.2070  (b)0.3798  (c) 0.3938 </em>

Step-by-step explanation:

<em>Given:</em>

<em>Here Section 1 students = 20 </em>

<em> Section 2 students = 30 </em>

<em> Here there are 15 graded exam papers. </em>

<em> (a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070 </em>

<em> (b) Here if x is the number of students copies of section 2 out of 15 exam papers. </em>

<em>  here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15 </em>

<em>Then, </em>

<em> Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798 </em>

<em> (c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1) </em>

<em> so, </em>

<em> Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938 </em>

<em> Note : Here the given distribution is Hyper-geometric distribution </em>

<em> where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.</em>

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