Question

In the parallelogram shown, AE = p − 8, CE = 2p − 58, and DE = p + 15. What is the length of line segment EB?

Answer 1

DE = EB

DE = p + 15

I would help you farther but I don't know what p equals. If you know then add that number with 15 and you have your answer.

Answer 2

The first thing we must do is find the value of p.

For this, we use the following equality:

$AE = EC$

Substituting values we have:

$p - 8 = 2p - 58$

Clearing the value of p we have:

$2p - p = 58 - 8\\p = 50$

Then, we look for the length of EB.

We know that:

$EB = DE$

Substituting values we have:

$EB = p + 15\\EB = 50 + 15\\EB = 65$

Answer:

the length of line segment EB is:

65 units