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posledela
3 years ago
15

Can some one please answer. There is one problem. There's a picture. Thank you!

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
7 0
The height is approx 5
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Solve (x + 3)2 + (x + 3) – 2 = 0. Let u = Rewrite the equation in terms of u. (u2 + 3) + u – 2 = 0 u2 + u – 2 = 0 (u2 + 9) + u –
Verdich [7]

Answer:

The solutions of the original equation are x=-5 and x=-2

Step-by-step explanation:

we have

(x+3)^2+(x+3)-2=0

Let

u=(x+3)

Rewrite the equation

(u)^2+(u)-2=0

Complete  the square

u^2+u=2

u^2+u+1/4=2+1/4

u^2+u+1/4=9/4

rewrite as perfect squares

(u+1/2)^2=9/4

square root both sides

(u+1/2)=\pm\frac{3}{2}

u=(-1/2)\pm\frac{3}{2}

u=(-1/2)+\frac{3}{2}=1

u=(-1/2)-\frac{3}{2}=-2

the solutions are

u=-2,u=1

<em>Alternative Method</em>

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

(u)^2+(u)-2=0

so

a=1\\b=1\\c=-2

substitute in the formula

u=\frac{-1\pm\sqrt{1^{2}-4(1)(-2)}} {2(1)}

u=\frac{-1\pm\sqrt{9}} {2}

u=\frac{-1\pm3} {2}

u=\frac{-1+3} {2}=1

u=\frac{-1-3} {2}=-2

the solutions are

u=-2,u=1

<em>Find the solutions of  the original equation</em>

For u=-2

-2=(x+3) ----> x=-2-3=-5

For u=1

1=(x+3) ----> x=1-3=-2

therefore

The solutions of the original equation are

x=-5 and x=-2

4 0
3 years ago
Read 2 more answers
Find the value of c that makes x^2–6x + c a perfect square trinomial and write as a binomial squared.
denpristay [2]

Answer: 9

Step-by-step explanation:

Given

The function is x^2-6x+c

To make it a perfect square, compare it with (a-b)^2=a^2+b^2-2ab

Here,

x=a,\\-6x=-2ab\\\\\therefore b=3

So, c must be square of b i.e. 9

x^2-6x+c\Rightarrow x^2-6x+9\\\Rightarrow (x-3)^2

Therefore, value of c is 9.

3 0
3 years ago
Can someone help me with this simple math problem, you can easily get points if you know the answer correctly. Also I will mark
Mekhanik [1.2K]

Answer:

RATIONAL

Step-by-step explanation:

8 0
3 years ago
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los trabajadores de una mina se encuentran a 20 metros bajo tierra .Si excavan 3 metros desde alli suben otros 8 metros para cog
Yakvenalex [24]

Step-by-step explanation:

la carretilla estaba a unos 15 metros de altura

8 0
2 years ago
Suppose the radius of a circle is 5.what is its diameter
Gnom [1K]
The diameter would be twice 5, or 10
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3 years ago
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