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mrs_skeptik [129]
3 years ago
6

What shape is generated when ABC is rotated around the vertical line through B and C ?

Mathematics
2 answers:
Leno4ka [110]3 years ago
8 0

Answer:

cone

Step-by-step explanation:

svetoff [14.1K]3 years ago
6 0

Answer:

a...

Step-by-step explanation:

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How do you write this number using digits?
jasenka [17]
Answer: 506,827

Explanation: Google
4 0
3 years ago
The ratio of the number of girls to the number of all students in the class is 4 to 9. Are there more boys or more girls in that
Alexxx [7]
If there are 4 girls to every 9 students, then there are 5 boys to every girl, 9-4=5. So, there are more boys in the class.
8 0
3 years ago
Read 2 more answers
Gerold invested $118 in an account that pays 6 percent simple interest. how much money will he have at the end of 5 years
JulsSmile [24]
If you would like to know how much money will Gerold have at the end of 5 years, you can calculate this using the following steps:

1 year: $118 + 6% * $118 = 118 + 6/100 * 118 = 118 + 7.08 = $125.08
2 year: $125.08 + 6% * $125.08 = 125.08 + 6/100 * 125.08 = 125.08 + 7.50 = $132.58
3 year: $132.58 + 6% * $132.58 = 132.58 + 6/100 * 132.58 = 132.58 + 7.95 = $140.53
4 year: $140.53 + 6% * $140.53 = 140.53 + 6/100 * 140.53 = 140.53 + 8.43 = $148.96
5 year: $148.96 + 6% * $148.96 = 148.96 + 6/100 * 148.96 = 148.96 + 8.94 = $157.9

The correct result would be $157.9.
6 0
3 years ago
PLS HELP ASAP THANKS ILL GIVE BRAINLKEST PLS THANKS PLS
kirill [66]
The answer should be (6,-1)

Explanation:

Focus on point A since it's asking for that. Then, shift it down vertically -8.

This means you are shifting A down 8 units.

Then they ask for a reflection across the y-axis. The y-axis is the vertical line in the middle, so to do this transformation, just change the x-value of where A is to the opposite.
4 0
2 years ago
Pls I need help with this
LiRa [457]

Answer:

third side = 4

Step-by-step explanation:

third side is hypoenuse as it is opposite to 90 degree.

using pythagoras theorem

(perpendicular)^2 + (base)^2 = (hypotenuse)^2

2^2 + (2\sqrt{3 )^2 = hypotenuse^2

4 + 4*3 = hypotenuse^2

16 = hypotenuse^2

\sqrt{16} = hypotenuse

4 = hypotensue

7 0
3 years ago
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