Hello from MrBillDoesMath!
Answer:
1/243
Discussion:
3^(-3) * 3^(-2) => as a^m * a^n = a^(m+n), the exponents add
= 3^ (-3 -2)
= 3^ (-5) =
= 1/ 3^5 => as 3^5 = 243
= 1/243
which is approximately .0041
Thank you,
MrB
Answer:
134°
Step-by-step explanation:
∠BAC = ∠BCA because it is an isosceles triangle
∠XCA = ∠XAC . Congruent angles
∠XAC = 1/2(46) = 23° . because CE bisects ∠ C
∠XCA = 23°
180° - 23° - 23° = 134° . Sum of all angles in a triangle is 180°
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-Chetan K
The number of days Ashley ate Mexican food while on vacation is 20 days.
<h3>How many days did Ashley eat mexican food?</h3>
The first step is to determine the fraction of the number of days Ashley atae Mexican food. In order to do this, divide 4 by 7
4/7.
The second step is to multiply 4/7 by 35
4/7 x 35= 20 days
To learn more about multiplication, please check: brainly.com/question/3385014
(x,y)
x=how far to the right
y=how far up
ok so
y=mx+b
m=slope
b=y intercept or where the line intercept the y axis
it looks like the line intercept the y axis at 2 high so
y=mx+2
we look at our options and we see that there is only 1 equation that has y=mx+2
that is B
B is the answer
Answer:
1100 field-side tickets and 4500 end-zone tickets.
Step-by-step explanation:
Let x represent number of field side tickets and y represent number of end-zone tickets.
We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:
![x+y=5600...(1)](https://tex.z-dn.net/?f=x%2By%3D5600...%281%29)
We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.
Cost of x field side tickets would be
and cost of y end-zone tickets would be
.
The total amount of money received for the tickets was $134000. We can represent this information in an equation as:
![40x+20y=134000...(2)](https://tex.z-dn.net/?f=40x%2B20y%3D134000...%282%29)
Upon substituting equation (1) in equation (2), we will get:
![40x+20(5600-x)=134000](https://tex.z-dn.net/?f=40x%2B20%285600-x%29%3D134000)
![40x+112000-20x=134000](https://tex.z-dn.net/?f=40x%2B112000-20x%3D134000)
![20x+112000=134000](https://tex.z-dn.net/?f=20x%2B112000%3D134000)
![20x+112000-112000=134000-112000](https://tex.z-dn.net/?f=20x%2B112000-112000%3D134000-112000)
![20x=22000](https://tex.z-dn.net/?f=20x%3D22000)
![\frac{20x}{20}=\frac{22000}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B20x%7D%7B20%7D%3D%5Cfrac%7B22000%7D%7B20%7D)
![x=1100](https://tex.z-dn.net/?f=x%3D1100)
Therefore, 1100 field side tickets were sold.
Upon substituting
in equation (1), we will get:
![y=5600-1100](https://tex.z-dn.net/?f=y%3D5600-1100)
![y=4500](https://tex.z-dn.net/?f=y%3D4500)
Therefore, 4500 end-zone tickets were sold.