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tatyana61 [14]
3 years ago
7

What are the answers too these questions

Mathematics
1 answer:
steposvetlana [31]3 years ago
8 0

Answer:

Step-by-step explanation:

i can't see it

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Daves first three test scores in algebra were 84%, 88%, and 90%. what does he need to earn on the next test so that his average
defon

Answer:

C gives you 90.2

Step-by-step explanation:

84+88+90+100=362

362/4=90.2

8 0
3 years ago
Use the reciprocal property to solve for x:
Natali5045456 [20]

Answer:

The answer is 1800.

Step-by-step explanation:

3/540 = 10/x

3x = 540 × 10

x = 5400/3

x = 1800

6 0
3 years ago
Which choice shows the product off 22 and 49?
liq [111]

Answer:

1,078

Step-by-step explanation:

I got that answer by multiplying 22 and 49. We know that product means to use the multiplication operation so our problem would look like this:

22 * 49 = 1,078

6 0
4 years ago
∠ and ∠ are supplementary angles. If ∠ = (2 − 30)° and ∠ = 4, find the measure of the larger angle
Gala2k [10]

Answer:

We get ∠A =40° and ∠B = 140° and ∠B = 140° is measure of larger angle

Step-by-step explanation:

we have  ∠A = (2x − 30)° and ∠B = 4x, and we need to find measure of larger angle. And ∠A and ∠A are supplementary angles.

If the angles are supplementary there sum is equal to 180° i.e ∠A + ∠B = 180°

So,  First we have to find the value of x. and then we can determine larger angle.

We know: ∠A + ∠B = 180

2x-30+4x=180

6x-30=180

6x=180+30

6x=210

x=210/6

x=35

So, value of x is x=35

Now finding ∠A and ∠B

∠A = (2x − 30)°

∠A = (2(35) − 30)°

∠A = (70 − 30)°

∠A =40°

and ∠B = 4x

∠B = 4(35)

∠B = 140°

So, we get ∠A =40° and ∠B = 140° and ∠B = 140° is measure of larger angle

6 0
3 years ago
Use undetermined coefficients to find the particular solution to 7t + 5=y''+y'-4y У, (t) - Preview Get help: Video Points possib
lions [1.4K]

Suppose y_p=a_0+a_1t is a solution to the ODE. Then {y_p}'=a_1 and {y_p}''=0, and substituting these into the ODE gives

a_1-4(a_0+a_1t)=7t+5\implies\begin{cases}-4a_1=7\\-4a_0+a_1=5\end{cases}\implies a_0=-\dfrac{27}{16},a_1=-\dfrac74

Then the particular solution to the ODE is

y_p=-\dfrac{27}{16}-\dfrac74t

5 0
3 years ago
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