If a triangle is made up of side lengths a, b and c
Given that c is the longest side length of the triangle,
The Pythagorean theorem can be used to tell if the triangle
is obtuse, acute or right
In an obtuse triangle,
a^2 + b^2 < c^2
In an acute triangle,
a^2 + b^2 > c^2
In a right angled triangle,
a^2 + b^2 = c^2
The probability that at most 8 of them take the bus to school is 0.925, written in percentage form this is 92.5%
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How to find the probability?</h3>
We know that roughly 75% of the students take the bus, then, if we select a student at random.
- There is a probability of 0.75 that the student takes the bus.
- There is a probability of 0.25 that the student does not take the bus.
The probability that at most 8 out of 9 students take the bus, is equal to one minus the probability of the 9 taking the bus, which is:
p = (0.75)^9 = 0.075
Then we have:
P = 1 - 0.075 = 0.925
The probability that at most 8 of them take the bus to school is 0.925, written in percentage form this is 92.5%
If you want to learn more about probability, you can read:
brainly.com/question/251701
Answer:
8 ≤ u ≤ 12
Step-by-step explanation:
Given:
C = 34.95u +6.25
Where,
u = number of uniforms
what is the domain you of the function for this situation
The number of uniforms depend on the number of players
If there are at least 8 players but not more than 12 players on the volleyball team.
u ≥ 8
u ≤ 12
The domain of the function is
8 ≤ u ≤ 12
What are the other expressions then I can help
Total number of ways to make a pair:
The first player can be any one of 7 . For each of those . . .
The opponent can be any one of the remaining 6 .
Total ways to make a pair = 7 x 6 = 42 ways .
BUT ... every pair can be made in two ways ... A vs B or B vs A .
So 42 'ways' make only (42/2) = 21 different pairs.
If every pair plays 2 matches, then (21 x 2) = <em><u>42 total matches</u></em> will be played.
Now, is that an elegant solution or what !
