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balandron [24]
4 years ago
8

Write a number that has a zero in the tens place. draw a quick picture for your number

Mathematics
2 answers:
iogann1982 [59]4 years ago
7 0
Draw a picture of the number 100?
stepladder [879]4 years ago
4 0
Ones tens hundreds
So what you need to do if it says tens place it would be
10
20
30
Two digits
One thru 90 but the second number has to be 0
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HELP ASAP! EXPONENTIAL FUNCTIONS
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It is the yellow one
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3 years ago
(-2/5)7÷(-2/5)5=????
Harman [31]

Answer:

\frac{4}{25}

Step-by-step explanation:

Using the rule of exponents

a^{m} ÷  a^{n} ⇔ a^{(m-n)}

Given

-2/5)^{7} ÷ (-2/5)^{5}

= (-2/5)^{(7-5)}

= (-2/5)^{2}

= - \frac{2}{5} × - \frac{2}{5} = \frac{4}{25}

3 0
3 years ago
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Dafna11 [192]

Answer:

that- y= 12/22x + 14, I think-

Step-by-step explanation:

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7 0
4 years ago
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Jason and Britton are driving to St. George. Jason got a 20 mile head start and drove an
harina [27]

Answer:

  2 hours, 150 miles

Step-by-step explanation:

The relation between time, speed, and distance can be used to solve this problem. It can work well to consider just the distance between the drivers, and the speed at which that is changing.

<h3>Separation distance</h3>

Jason got a head start of 20 miles, so that is the initial separation between the two drivers.

<h3>Closure speed</h3>

Jason is driving 10 mph faster than Britton, so is closing the initial separation gap at that rate.

<h3>Closure time</h3>

The relevant relation is ...

  time = distance/speed

Then the time it takes to reduce the separation distance to zero is ...

  closure time = separation distance / closure speed = 20 mi / (10 mi/h)

  closure time = 2 h

Britton will catch up to Jason after 2 hours. In that time, Britton will have driven (2 h)(75 mi/h) = 150 miles.

__

<em>Additional comment</em>

The attached graph shows the distance driven as a function of time from when Britton started. The distances will be equal after 2 hours, meaning the drivers are in the same place, 150 miles from their starting spot.

3 0
2 years ago
In the lab, Goran has two solutions that contain alcohol and is mixing them with each other. Solution A is 40% alcohol and Solut
bogdanovich [222]

Answer:

400milliliters

Step-by-step explanation:

Let x=ml of 30% solution B used in resulting mixture.

800+x=ml of resulting 30% solution

40%(800)+10%x=30%(800+x)

Then we can simplify the expression

0.4(800)+0.10x= 0.30(800+x)

320+0.10x=240+0.30x

80=0.20x

x= 400milliliters

Therefore, 400milliliters of 10% solution B used in resulting mixture.

4 0
4 years ago
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