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balandron [24]
3 years ago
8

Write a number that has a zero in the tens place. draw a quick picture for your number

Mathematics
2 answers:
iogann1982 [59]3 years ago
7 0
Draw a picture of the number 100?
stepladder [879]3 years ago
4 0
Ones tens hundreds
So what you need to do if it says tens place it would be
10
20
30
Two digits
One thru 90 but the second number has to be 0
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What is the answer of the equation 234+(-234).
Radda [10]

Answer:

It would be 0

Step-by-step explanation:

234+(-234) = 0

unless you meant the absolute value of -234

then it would be 468

8 0
3 years ago
Read 2 more answers
Solve using any method. All work must be shown and handwritten.
Rashid [163]

Answer:

x =  - 3

y = 1

Step-by-step explanation:

Write the system

3x - y =  - 10

x + y =  - 2

Solve by Elimination.

multiply the second equation by -3.

3x - y =  - 10

-3x   - 3y =  6

Add the Equations.

- 4y =  - 4

y = 1

Plug this back in one of the equations.

x + 1 =  - 2

x =  - 3

8 0
2 years ago
Read 2 more answers
A person in a balloon which is 2,000 feet above the airport finds that the angle of depression to a ship out at sea is 21°. Find
maria [59]
The horizontal distance is given by the formula:
tan θ=opposite/adjacent
where:
θ=21
opposite=2000 ft
adjacent=a
thus calculating for a we get:
tan 21=2000/a
thus
a=2000/tan 21
a=5210.18 ft

Answer: 5210.18 ft
4 0
3 years ago
Read 2 more answers
H(t)= (t+3)^2 + 5
oee [108]

Answer:

The average rate of change for the given function in the interval (-5, -1) is 0 (zero)

Step-by-step explanation:

The average rate of change of a function over an interval is the quotient between the difference between the function evaluated at the ends of the interval divided by the length of the interval. That is for our case:

the average rte of change of h(t) in the interval (-5, -1) is:

\frac{h(-1)-h(-5)}{-1+5}

so we find:

h(-1)=(-1+3)^2+5=2^2+5=4+5=9\\and\\h(-5)=(-5+3)^2+5=(-2)^2+5=4+5=9

then the average rate of change becomes:

\frac{h(-1)-h(-5)}{-1+5}=\frac{9-9}{4} =\frac{0}{4} =0

5 0
3 years ago
A lot is 60 m by 38 m. A house 32 m by 9 m is built on the lot. How much area is left over?
OLEGan [10]

Answer:

1992

Step-by-step explanation:

60x38=2280

32x9=288

2280-288=1992

Hope it helps!

3 0
2 years ago
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