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3 years ago

You don't need to explain.

Mathematics

1 answer:

Sergeu [11.5K]3 years ago

5 0

Answer:

x=1

x y

---------------

1 1

2 2

3 3

4 4

5 5

etc.

Step-by-step explanation:

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The school that Jack goes to is selling tickets to a choral performance. On the first day of ticket sales the school sold 9 seni

raketka [301]

Answer:

Price of a senior citizen ticket is $4 and price of a student ticket is $15 .

Step-by-step explanation:

Let us assume that the price a senior citizen ticket be x .

Let us assume that the price a student citizen ticket be y .

As given

The school that Jack goes to is selling tickets to a choral performance.

On the first day of ticket sales the school sold 9 senior citizen tickets and 8 student tickets for a total of $156.

Equtaions becomes

9x + 8y = 156

As given

The school took in $163 on the second day by selling 7 senior citizen tickets and 9 student tickets.

Equations becomes

7x + 9y = 163

Multipy 9x + 8y = 156 by 9 .

81x + 72y = 1404

Multiply 7x + 9y = 163 by 8 .

56x + 72y = 1304

Subtracted 56x + 72y = 1304 from 81x + 72y = 1404 .

81x - 56x + 72y - 72y = 1404 - 1304

25x = 100

$x = \frac{100}{25}$

x = $ 4

Putting value of x in the 56x + 72y = 1304 .

56 × 4 + 72y = 1304

224 + 72y = 1304

72y = 1304 - 224

72y = 1080

$y = \frac{1080}{72}$

y = $15

Therefore the price of a senior citizen ticket is $4 and price of a student ticket is $15 .

5 0

3 years ago

“An architect is planning to incorporate several stone spheres of different sizes into the landscaping of a public park, and wor

Artist 52 [7]

Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

we know that

The circumference of a circle is equal to

$C=2\pi r$

Find the radius of the sphere with a 5.50-meter circumference

For $C=5.50\ m$

assume

$\pi =3.14$

substitute and solve for r

$5.50=2(3.14)r$

$r=5.50/[2(3.14)]=0.88\ m$

Find the radius of the sphere with a 7.85-meter circumference

For $C=7.85\ m$

assume

$\pi =3.14$

substitute and solve for r

$7.85=2(3.14)r$

$r=7.85/[2(3.14)]=1.25\ m$

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

$SA=4\pi r^{2}$

Find the surface area of sphere with a 5.50-meter circumference

For $r=0.88\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(0.88)^{2}$

$SA=9.73\ m^{2}$

Find the surface area of sphere with a 7.85-meter circumference

For $r=1.25\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(1.25)^{2}$

$SA=19.63\ m^{2}$

step 3

Find the cost of finishing each sphere

we know that

To find out the cost , multiply the surface area by $92 per square meter

Find the cost of sphere with a 5.50-meter circumference

$9.73*(92)=\$895.16$

therefore

The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Find the cost of sphere with a 7.85-meter circumference

$19.63*(92)=\$1,805.96$

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

6 0

3 years ago

A 35 year old mother realized that her age is twice the sum of her two children's age her son Jose is two year old than her daug

Drupady [299]

Answer:

Step-by-step explanation:

4 0

3 years ago

Help me pleasee i need help this is my final btw

Molodets [167]

Answer:

12 sq units

Step-by-step explanation:

height = 3

length = 4

A = l · w

A = 12

5 0

3 years ago

1 and 2 please and explain

baherus [9]

I'm sorry I don't know but you can use photomath you can just download it from the App

3 0

3 years ago