The sample space has 36 possible pairs from 1,1 1,2 1,3 up to 6,5 and 6,6
(a). Three pairs add to 4 1,3 2,2 and 3,1 so P(4) = 3/36 = 1/12
(b). 6 pairs add to 7 so P(7) = 6/36 = 1/6
(c) 15 pairs add to less than 7 so P(<7) = 15/36 = 5/12
Answer:
The probability that a ship that is declared defecive is sound is 0.375
Step-by-step explanation:
Let P(A|B) denote the conditional probability of A given B. We will make use of the equation
P(A|B) = P(A) × P(B|A) / P(B)
We have the probabilities:
- P(Declared Defective (detected) | Defective) = 0.95
- P(not Detected | Defective) = 1-0.95=0.05
- P(Declared Sound | Sound) = 0.97
- P(Declared Defective |Sound) = 1-0.97=0.03
We can calculate:
P(Declared Defective)= P(Detected | Defective)×P(Defective) + P(Declared Defective |Sound) ×P(Sound) = 0.95×0.05 + 0.03×0.95=0.076
P(S | Declared Defective) =
(P(Sound) × P(Declared Defective | Sound)) / P(Declared Defective)
=0.95×0.03 /0.076 =0.375
Answer:
Independent variable: C
Dependent Variable: M
Step-by-step explanation:
Lets begin with the Independent variable, C. C is moreover a result, so it remains as a dormant number that is yet to be known. M which is the dependent variable, contributes to the corresponding number we call the cost. When M , a quantity that is being manipulated the number 0.6, multiplies "per mile" plus 25. The actual expression is 25 + 0.6m, and the indpendent variable is known as the numerical coefficient.
