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pashok25 [27]
3 years ago
5

Graph y=2/5x, use x as -2,-1,0,1,2

Mathematics
1 answer:
Natali [406]3 years ago
4 0

Plot a graph of y-axis against x-axis.

The graph should be a straight line passing through:

(-2,0.8) , (-1,-0.4) , (0,0) , (1,0.4) and (2,0.8)

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How many possibly outcomes of flipping a coin four times?
vodka [1.7K]

8 times because you take 4 times 2 and get 8

5 0
3 years ago
Read 2 more answers
Question 12
Anestetic [448]
40 kilometers I think
4 0
3 years ago
Two cylinders are shown below which cylinder has a greater volume use 3.14 for pi
lesya [120]

Answer:

Cylinder Q has a greater volume

Step-by-step explanation:

For this question we need to utilise the volume of a cylinder which is

→ Volume of a cylinder = π × r² × h

Let's substitute in the values and then do the analysis

<u>Cylinder P</u>

→ Volume of a cylinder = π × r² × h

⇒ Substitute in the values

→ Volume of a cylinder = π × 4.25² × 14

⇒ Simplify

→ Volume of a cylinder = 794.430242277

<em>The volume of cylinder P is 794.430242277</em>

<em>-------------------------------------------------------------------------------------------------------</em>

<u>Cylinder Q</u>

→ Volume of a cylinder = π × r² × h

⇒ Substitute in the values

→ Volume of a cylinder = π × 7² × 8.5

⇒ Simplify

→ Volume of a cylinder = 1308.47334022

<em>The volume of cylinder Q is 1308.47334022</em>

<em>-------------------------------------------------------------------------------------------------------</em>

We can see that cylinder Q has a greater volume

8 0
3 years ago
A triangle ABC has its vertices at A(-2, -3), B(2, 1), and C(5,-1).
maksim [4K]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill ~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-3})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{1}) ~\hfill AB=\sqrt{( 2- (-2))^2 + ( 1- (-3))^2} \\\\\\ AB=\sqrt{(2+2)^2+(1+3)^2}\implies AB=\sqrt{32}\implies \boxed{AB=4\sqrt{2}} \\\\[-0.35em] ~\dotfill

B(\stackrel{x_1}{2}~,~\stackrel{y_1}{1})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{-1}) ~\hfill BC=\sqrt{( 5- 2)^2 + ( -1- 1)^2} \\\\\\ BC=\sqrt{3^2+(-2)^2}\implies BC=\sqrt{9+4}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{5}~,~\stackrel{y_1}{-1})\qquad A(\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3}) ~\hfill CA=\sqrt{( -2- 5)^2 + ( -3- (-1))^2} \\\\\\ CA=\sqrt{(-7)^2+(-3+1)^2}\implies CA=\sqrt{49+(-2)^2}\implies \boxed{CA=\sqrt{53}}

\stackrel{\textit{\large perimeter of ABC}}{4\sqrt{2}+\sqrt{13}+\sqrt{53}~~\approx~~ 16.54}

3 0
2 years ago
What are the possible rational roots of the polynomial equation?<br><br> 0=2x7+3x5−9x2+6
RoseWind [281]

Answer: \pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

a_nx^n +a_{n- 1}x^{n - 1} + … + a_1x^1 + a_0 = 0

Where:

- The coefficients are integers.

- a_n is the leading coeffcient (a_n\neq 0)

- a_0 is the constant term a_0\neq 0

Every rational root of the polynomial is in the form:

\frac{p}{q}=\frac{\pm(factors\ of\ a_0)}{\pm(factors\ of\ a_n)}

For the case of the given polynomial:

2x^7+3x^5-9x^2+6=0

We can observe that:

- Its constant term is 6, with factors 1, 2 and 3.

- Its leading coefficient is 2, with factors 1 and 2.

 Then, by Rational Roots Test we get the possible rational roots of this polynomial:

\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

5 0
3 years ago
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