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Harman [31]
3 years ago
15

I need help with linear inequalities one question. the question is -7x-86 less than -93.

Mathematics
1 answer:
Andreyy893 years ago
5 0
-7x<-93+86
-7x<-7
x>1 is the answer

DO YOU NEED TO GRAPH TOO? 
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HEEEEEEEEEEEELP <br> PWEEEEEEEEEEEZ
nadya68 [22]

Answer: D) Full circle on -2 and arrow pointing to the right.

Step-by-step explanation:

-\frac{5}{2}x -3\leq 2

add 3

-\frac{5}{2}x \leq 2+3

-\frac{5}{2}x \leq 5

multiply by the negative reciprocal of the fraction. (<u>NOTE:</u> When multiplying or dividing by negative numbers, the inequality sign flips.)

(-\frac{2}{5}) -\frac{5}{2}x \leq 5(-\frac{2}{5})

x\geq -2

This tells us that x has to be greater than or equal to -2

4 0
4 years ago
Trig Ratios see attachment
frutty [35]

Answer:

TanA = 5/12, SinA = 5/13

Step-by-step explanation:

Tangent is opposite/adjacent, so 5/12

Sin is opposite/hypotenuse, so 5/13

Hopefully this helps! Let me know if you have any questions

3 0
3 years ago
What are the vertical asymptotes of the function f(x) = the quantity of 5 x plus 5, all over x squared plus x minus 2?
tia_tia [17]
So basically 5x+5/(x)(x)-2.  the integers involving vertical movement I think would be 5 and -2
3 0
3 years ago
Read 2 more answers
Help is required, I am stuck
Natalija [7]

Answer:

see explanation

Step-by-step explanation:

Given

x² + 4x - 7 = 0 ( add 7 to both sides )

x² + 4x = 7

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(2)x + 4 = 7 + 4

(x + 2)² = 11 ( take the square root of both sides )

x + 2 = ± \sqrt{11} ( subtract 2 from both sides )

x = - 2 ± \sqrt{11}

Thus

x = - 2 - \sqrt{11} ≈ - 5.32 ( to 2 dec. places )

x = - 2 + \sqrt{11} ≈ 1.32 ( to 2 dec. places )

8 0
3 years ago
Help plz and teach me how to answer
professor190 [17]
She subtracted on the right side, when she should've added.

The answer is B
"Helen should have added 17 to both sides of the equation."
6 0
4 years ago
Read 2 more answers
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