Answer:
see explanation
Step-by-step explanation:
To find the zeros let p(x) = 0 , that is
(x² - 1)(x² - 5x + 6) = 0
Factorise each factor
x² - 1 ← is a difference of squares and factors as (x - 1)(x + 1)
x² - 5x + 6 = (x - 2)(x - 3), thus
(x - 1)(x + 1)(x - 2)(x - 3) = 0
Equate each factor to zero and solve for x
x - 1 = 0 ⇒ x = 1
x + 1 = 0 ⇒ x = - 1
x - 2 = 0 ⇒ x = 2
x - 3 = 0 ⇒ x = 3
The zeros are x = ± 1, x = 2, x = 3
Answer:
174
Step-by-step explanation:
thanks for the help guys
Answer:
Sorry but I don't know the answer too this question
Symbol i we call imaginary unit =>
This is basic
i^2= i * i = -1
i^3= i^2 * i = -1 * i = - i
i^4= i^3 * i = -i * i = - (i * i )=- (i^2)= - (-1) = 1
i^5= i^4 * i = 1 * i = i
i^6= i^5 * i = i * i = i^2 = -1
i^7= i^6 * i = -1 * i = - i
i^8= i^7 * i = -i * i = -(i * i)= -( i^2)= - (-1) = 1
You have all you need.
You conclude which simplifications of the power i are correct.
Good luck!!!!
