It would be true because 10,000-99,999=-89999 -89999<0 is true
Answer:
No
Step-by-step explanation:
No, because the perimeter of a rectangle is 2(x+y). Justin added the sides. Then he should have multiplied by 2 but he didn't so Justin is incorrect.
Hope this helps plz mark brainliest :D
Answer:
i think 1/300
Step-by-step explanation:
If a2 -2ab + b2 = 9 and a![\begin{gathered} a^2-2ab+b^2=9 \\ aStep 1 factorize[tex]\begin{gathered} a^2-2ab+b^2=(a-b)^2 \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20a%5E2-2ab%2Bb%5E2%3D9%20%5C%5C%20a%3C%2Fp%3E%3Cp%3E%EF%BB%BFStep%201%20%3C%2Fp%3E%3Cp%3Efactorize%3C%2Fp%3E%5Btex%5D%5Cbegin%7Bgathered%7D%20a%5E2-2ab%2Bb%5E2%3D%28a-b%29%5E2%20%5C%5C%20%20%5Cend%7Bgathered%7D)
then
[tex]\begin{gathered} (a-b)^2=9 \\ \sqrt{(a-b)^2}=\sqrt{9} \\ a-b=\pm3 \\ \\ aa-b=-3
Change each of the fractions into decimals.
1/8 becomes 0.125
-1/7 becomes -0.143
and -0.02555
0.2
In order from least to greatest,
-0.143, -0.02555, 0.125, 0.2
OR
-1/7, -0.02555, 1/8 and 0.2