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gregori [183]
4 years ago
15

Creating box plots

Mathematics
1 answer:
Tema [17]4 years ago
7 0

Answer:

100%

Step-by-step explanation: box one because your mutiplying the 100% by 1

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Cual es el perimetro y area de una llanta de 60 cm​
irga5000 [103]

Answer:

para un diámetro de 40 cm el perímetro es de 125.66 cm,

4 0
3 years ago
Use the image below to answer the following question. Find the value of sin x^0 and cos y^0. What relationship do the ratios of
gregori [183]

Answer:

sin x = 3/5

cos y  = 3/5

sin x and cos y are equal

Step-by-step explanation:

First we need to find the length of the hypotenuse

We can use the Pythagorean  theorem

a^2+ b^2 = c^2  where a and b are the legs and c is the hypotenuse

6^2 +8^2 = c^2

36+64 = c^2

100 = c^2

Taking the square root

sqrt(100) = sqrt(c^2)

10 = c

The hypotenuse is 10

Since this is a right triangle we can use trig functions

sin x = opp side/ hypotenuse

sin x = 6/10 = 3/5

cos y = adj / hypotenuse

cos y = 6/10  = 3/5

sin x and cos y are equal

4 0
3 years ago
Read 2 more answers
Which of the following is not a function?
____ [38]

Answer:D

Step-by-step explanation:

D, the  X values repeat for 7.

5 0
3 years ago
Subtract rational expression. <br> Show work please.
yan [13]

Given:

$\frac{x+4}{x-1}-\frac{5}{x^{2}-1}

To find:

The simplified rational expression by subtraction.

Solution:

Let us factor x^2-1. It can be written as x^2-1^2.

x^2-1^2=(x-1)(x+1) using algebraic identity.

$\frac{x+4}{x-1}-\frac{5}{x^{2}-1}=\frac{x+4}{x-1}-\frac{5}{(x+1)(x-1)}

LCM of x-1,(x+1)(x-1)=(x+1)(x-1)

Make the denominators same using LCM.

Multiply and divide the first term by (x + 1) to make the denominator same.

                        $=\frac{(x+4)(x+1)}{(x-1)(x+1)}-\frac{5}{(x-1)(x+1)}

Now, denominators are same, you can subtract the fractions.

                        $=\frac{(x+4)(x+1)-5}{(x-1)(x+1)}

Expand (x+4)(x+1)-5.

                        $=\frac{x^2+4x+x+4-5}{(x-1)(x+1)}

                        $=\frac{x^{2}+5 x-1}{(x-1)(x+1)}

$\frac{x+4}{x-1}-\frac{5}{x^{2}-1}=\frac{x^{2}+5 x-1}{(x-1)(x+1)}

6 0
3 years ago
Jen knows that (-1, 41) and (5, 41) lie on a parabola defined by the equation y=4x^2-16x+21. How can I find the coordinates of t
andreyandreev [35.5K]
The vertex is at (2, 5).

To find the vertex, we first find the axis of symmetry; this is given by

x = -b/2a

For our equation, b = -16 and a = 4:
x = -(-16)/2(4) = 16/8 = 2

We substitute this back into our equation:
y = 4(2)² - 16(2) + 21 = 4(4) - 32 + 21 = 5

Therefore the vertex is at (2, 5).
8 0
3 years ago
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