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AlekseyPX
3 years ago
15

For which value of x is the equation 2(1 + x) = x + 3 true? A) 1 B) 2 C) 3 D) 4

Mathematics
1 answer:
amm18123 years ago
5 0

Answer:

A) 1

Step-by-step explanation:

To solve, just plug in the numbers to the equation for x until both sides are equal to each other.

Plug in 1:

2(1 + x) = x + 3

Let x = 1:

2(1 + 1) = 1 + 3

Solve. Remember to follow PEMDAS. First, add parenthesis, then multiply. On the other side, add:

2(1 + 1) = 1 + 3

2(2) = 4

4 = 4 (True)

A) 1 is your answer.

~

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Answer:

  a) $169,234.59

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Step-by-step explanation:

The first question you must answer is whether Colleen will earn interest on her first deposit in the first year. That is, does she deposit the money at the first of the year or the end of the year?

The usual "annuity" formula assumes the deposit is at the end of the year, so no interest at all is earned on the last deposit made. If the deposit is at the first of the year, an "annuity due" formula is used, that multiplies the entire ending account value by the annual multiplier, 1.017 in this case.

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a) Assuming an "annuity", the formula is ...

  A = P((1 +r)^t -1)/r . . . . . for annual compounding at rate r for t years

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3 years ago
Which expressions are equivalent to 3 (3P+3 - 3P-5) ? choose ALL that apply.
Stels [109]

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Tom simplified an expression in three steps, as shown: x to the power of negative 2 multiplied by y to the power of 4, over y mu
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Answer:

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Step-by-step explanation:

<u>The three steps are</u>

  1. (x⁻² × y⁴ /y × x⁴ × x⁴ × y⁻²)⁴ =  
  2. x²×y⁸/y⁴×x⁸×x⁸×y² =
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<u>Correct solution should be:</u>

  • (x⁻² × y⁴ /y × x⁴ × x⁴ × y⁻²)⁴ =  all powers inside the parenthesis should be multiplied by 4 as per power of the power  (xᵃ)ᵇ = xᵃᵇ

<u>This would give next steps:</u>

  1. x⁻⁸×y¹⁶/y⁴×x⁸×x⁸×y⁻⁸ =
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<u>Answer options:</u>

Step 1, all the exponents are increased by 4

  • There should be multiplication of powers. (It is close option but is not fully correct as not all the exponents increased by 4, for example y became y⁴)

Step 2, the exponents of the same base are added during multiplication

  • It was done correctly

Step 3 wasn't performed yet, there was step 1 and 2.

  • So answers about step 3 are irrelevant
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