The bus drops Nigel off 64 miles away from the school.
Step by step Explanation:
An equation for this would be 312-14-234 (this was the equation I used. Since you would do left to write to solve the equation, you would do, 312-14 which equals 298. Then, the equation is left as 298-234, and when you solve that part to the equation, yoh would be getting 64. And that's how you would get the answer 64miles away from the school.
Answer:
c- translation
Step-by-step explanation:
it just moved a few points down
<h3>Given</h3>
A(-3, 1), B(4, 5)
<h3>Find</h3>
coordinates of P on AB such that AP/PB = 5/2
<h3>Solution</h3>
AP/PB = 5/2 . . . . . desired result
2AP = 5PB . . . . . . multiply by 2PB
2(P-A) = 5(B-P) . . . meaning of the above
2P -2A = 5B -5P . . eliminate parentheses
7P = 2A +5B . . . . . collect P terms
P = (2A +5B)/7 . . . .divide by the coefficient of P
P = (2(-3, 1) +5(4, 5))/7 . . . . substitute the given points
P = (-6+20, 2+25)/7 . . . . . . simplify
P = (2, 3 6/7)
With the given hint to be able to answer the question above, the equation for Newton's law of cooling is as follows:
T(t) = T(s) + (T0 - Ts)e^-kt
where T(t) is the body's temperature at any given time, Ts is the temperature of the surrounding, T0 is the initial temperature, and k is constant.
Substituting the values with the given above,
T(t) = 76 + (170 - 76)*e^(-0.34)(7)
This gives us the answer,
T(t) = 84.7 degrees F
