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aleksandr82 [10.1K]
3 years ago
5

Solve this equation. 5³ + (-19) (2) = 6

Mathematics
2 answers:
DochEvi [55]3 years ago
7 0
False 87≠6 is this equation written correctly?
Neporo4naja [7]3 years ago
4 0

Answer:

500 +19-2= 517

Step-by-step explanation:

if that was the qeustion theirs the answer

: ) HOPE I COULD HELP

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ABC is translated 5 units up and 1 unit right. Find the coordinates of the reflected image.
4vir4ik [10]

Answer:

A

Step-by-step explanation:

A(3-5) B. (-1,-4) C. (-1,-5)

8 0
3 years ago
find the length of the base of a square pyramid if the volume is 1,024 cubic inches and has a height of 12 inches
Tju [1.3M]
Let 's x the length of the pyramid:
V=x²*h/3
V=1024 and h=12
So x²*12/3=1024
==>x²=1024*3/12
==>x²=256
==>x²=16²
==> x=16 for (x=-16 must be exclude <0)

......brainpower pts pls
7 0
3 years ago
Read 2 more answers
X + 4y = 16 and 2x + 12y = 48 What is the value of x+y in the solution of the system?
likoan [24]

Answer:

x = − 4y + 16

x = − 6y + 24

Step-by-step explanation:

Let's solve for x.

x + 4y = 16

Step 1: Add -4y to both sides.

x + 4y + − 4y = 16 + − 4y

x = − 4y + 16

Answer:

x = − 4y + 16

Let's solve for x.

2x + 12y = 48

Step 1: Add -12y to both sides.

2x + 12y + − 12y = 48 + − 12y/2x= − 12y + 48

Step 2: Divide both sides by 2.

2x/2 = − 12y + 48/2x = − 6y + 24

Answer: x = − 6y + 24

( I hope this was helpful) >;D

8 0
3 years ago
Simplify the radical expression.<br> - V8n•2 12
Sholpan [36]
The answer is in the photo below

6 0
3 years ago
[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation
irina1246 [14]

Answer:

y=-\frac{158}{579}

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]

And the vector B is formed with the solution of each equation of the system:b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called A_{2}.

A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]

The value of y using Cramer's rule is:

y=\frac{det(A_{2}) }{det(A)}

Find the value of the determinant of each matrix, and divide:

y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}

y=-\frac{158}{579}

7 0
4 years ago
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