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2 years ago

Can someone help me with this equation a+2/2=-1

Mathematics

2 answers:

Vedmedyk [2.9K]2 years ago

8 0

A is -2, because 2/2 is 1, and -2+1 is -1

Nadusha1986 [10]2 years ago

3 0

Hi there, please give me the branliest answer if I helped. The photo is attached below.

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nikitadnepr [17]

Answer:

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Step-by-step explanation:

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1 year ago

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2 years ago

Find the exact value of sin2 theta given sin theta =5/13, 90°<theta <180°

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Now, we know that 90°< θ <180°, that simply means the angle θ is in the II quadrant, where sine is positive and cosine is negative.

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{13}}\impliedby \textit{now let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
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a=adjacent\\
b=opposite\\
\end{cases}$

$\bf \pm\sqrt{13^2-5^2}=a\implies \pm\sqrt{144}=a\implies \pm 12 =a \implies \stackrel{II~quadrant}{-12=a}
\\\\\\
therefore \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{-12}}{\stackrel{hypotenuse}{13}}
\\\\
-------------------------------\\\\
sin(2\theta )\implies 2sin(\theta )cos(\theta )\implies 2\left(\frac{5}{13} \right)\left( \frac{-12}{13} \right)\implies -\cfrac{120}{169}$

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alisha [4.7K]

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Hope it helps <3

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2 years ago