Answer:
4.9 m
Step-by-step explanation:
Resolvemos la pregunta anterior usando la función trigonométrica de seno
sin θ = Opuesto / Hipotenusa
θ = 78 °
Hipotenusa = Longitud de la escalera = 5 m
Opuesto = Distancia sobre el suelo = x
sin 78 = x / 5m
Multiplicar cruzada
x = sin 78 × 5 m
x = 4.8907380037m
Aproximadamente
= 4.9 m
$5 for reg
$10 for mid
$15-$20 for loud
Answer:
66
Step-by-step explanation:
We can write the following equation to solve

Reduce
360 = 5x + 30
5x = 330
x = 66
Answer:
Distance around the pool = 162.8 feet
Area of the pool = 957 square feet
Step-by-step explanation:
Distance around the swimming pool = Perimeter of the pool
Perimeter of the pool which is a composite figure will be,
= Circumference of the semicircle + Sum of three sides of the pool
= πr + 2×(length of the pool) + width of the pool
= 3.14×(10) + 2×40 + 20
= 62.8 + 80 + 20
= 162.8 ft
Area of the pool = Area of the semicircle + Area of the rectangular pool
= 
= 
= 157 + 800
= 957 square feet
Answer:
- after week 7: 4374 pennies
- 486 pennies: after week 5
Step-by-step explanation:
The sequence values have a first term of 6 and a common ratio of 3, so can be described by the formula ...
an = 6·3^(n-1)
This can be rearranged to ...
an = 2·3^n
__
When n=7, the value is ...
a7 = 2·3^7 = 4374 . . . . pennies saved after 7 weeks
__
To find when there are 486 pennies saved, we can solve the equation ...
486 = 2·3^n
243 = 3^n
log(243) = n·log(3) . . . . . . . take the logarithm
log(243)/log(3) = n = 5 . . . . divide by the coefficient of n
Tabitha will have saved 486 pennies after 5 weeks.