Basically you just have to do 100*3=300 (* multiply)
The sum of first 20 terms of Arithmetic Series is 650 if the first term is 4 and the common difference is 3.
Step-by-step explanation:
First Term (a) = 4
Common difference (d) = 3
The number of term (n) = 20
The sum of an Arithmetic series of (n) number of terms, with first term (a) and the common difference (d) is equal to
Sum = (n/2) * ( 2 * a + (n -1) * d)
So putting the values of a,d, n
Sum = ( 20/2) * ( 2 * 4 + (20 -1) *3 )
Sum = (10) * ( 8 + 19 * 3)
Sum = 10 * ( 8 + 57)
Sum = 10 * 65 = 650
Hence the sum of first 20 terms of Arithmetic Series is 650 if the first term is 4 and the common difference is 3.
Answer:
f=15
Step-by-step explanation:
set 2.5 over 1 to make it a fraction and cross multiply
I believe the method that can be used is Side- side- side or (SSS).
Triangle QRX is similar to triangle TSX.
I hope that helps you!! Any more questions??
