Answer:
For the average to be above 90, the marks in the fourth paper should be MORE THAN 92.
Step-by-step explanation:
The score of students in last 3 exams = 89 , 87 and 92
Let us assume the marks scored by the student in last exam = k
The average of marks should be above 90.
Now, 
Sum of all 4 paper's marks = 89 + 87 + 92 + k = 268 + k
Also, 90 < Average
Hence,for the average to be above 90, the marks in the fourth paper should be MORE THAN 92.
Answer:
3 + 2 = 5
add x to 5
5x + 2x to the 2nd power
2 times 2 = 4x = 5 and 4x
5x + 4x
8x^2+6x^2+4x=138 combine like terms on left side
14x^2+4x=138 since the number of seats in the from row is just 4x, subtract 14x^2 from both sides
4x=138-14x^2 that would be the general solution, if you wanted the actual number you would have to solve for x and then multiply that value by 4 to know what "4x" is...
14x^2+4x-138=0
14x^2-42x+46x-138=0
14x(x-3)+46(x-3)=0
(14x+46)(x-3)=0
2(7x+23)(x-3)=0, since x>0
x=3 and thus
4x=12 seats
So there are 12 seats in the front row addition.
Answer:120
Step-by-step explanation:
calculate the sum of the negetive numbers 3x-40
=120
Answer:
The radical notation is ![3x\sqrt[3]{y^2z}](https://tex.z-dn.net/?f=3x%5Csqrt%5B3%5D%7By%5E2z%7D)
Step-by-step explanation:
Given
![\sqrt[3]{27 x^{3} y^{2} z}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%20x%5E%7B3%7D%20y%5E%7B2%7D%20z%7D)
Step 1 of 1
Write the expression using rational exponents.
![\sqrt[n]{a^{m}}=\left(a^{m}\right)^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%7D%3D%5Cleft%28a%5E%7Bm%7D%5Cright%29%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Simplify 
![$=3 x \sqrt[3]{y^{2} z}$](https://tex.z-dn.net/?f=%24%3D3%20x%20%5Csqrt%5B3%5D%7By%5E%7B2%7D%20z%7D%24)
Learn more about radical notation, refer :
brainly.com/question/15678734
