All categories

3 years ago

Giving best answer brainliest

Mathematics

2 answers:

kipiarov [429]3 years ago

8 0

Answer:

$365.00

Step-by-step explanation:

P= 300

r= 4/100

t=5

Hence, A= P(1+r)^t

A = 300(1+0.04)^5

A= 300(1.04)^5

A= $364.99587..

Rounded answer would be $365.00

Hope this helps!

Please mark brainliest if you think I helped! Would really appreciate!

fgiga [73]3 years ago

4 0

Answer

A= P(1 + r)^t

Principal= $300

rate= 4%

time= 5year

A= 300(1 + 4)^5

= 300 + 20

= $320

Step-by-step explanation:

You might be interested in

5b + 7a + 15 - a + 2b - 10

Margarita [4]

Answer: i think its 7b+7a+15 - a - 10 and 7(8j + 5) -12

Step-by-step explanation:

7 0

2 years ago

3 6/4 in simplest form

ivanzaharov [21]

Answer:

4 1/2.

hope this helps!

6 0

2 years ago

What is the approximate length of AB?

liq [111]

Answer:

Step-by-step explanation:

1. go to desmos Graphing calculator and select graphing calculator

2. Next type in the word length then it should look like this Length

3. Don't space just put this ( and type in the point it should look like this Length(-2,-3),(4,4)

4. Be sure to do double () it should look like this Length((-2,-3),(4,4))

5. It should give you your answer

6 0

1 year ago

What are the domain, range, and asymptote of h(x) = 6x – 4?

Lelechka [254]

Domain: (-infinity, infinity)
Range: (-infinity, infinity)
Asymptote: none

8 0

3 years ago

What set of reflections would carry hexagon ABCDEF onto itself?

Marianna [84]

When a set of reflections that carry a shape onto itself, it means that the final position of the shape will be the same as its original location

Reflections (a) y=x, x-axis, y=x, y-axis would carry the hexagon onto itself

First; we test the given options, until we get the true option

(a) y=x, x-axis, y=x, y-axis

The rule of reflection y =x is:

$(x,y) \to (y,x)$

The rule of reflection across the x-axis is:

$(x,y) \to (x,-y)$

So, we have:

$(y,x) \to (y,-x)$

The rule of reflection y =x is:

$(x,y) \to (y,x)$

So, we have:

$(y,-x) \to (-x,y)$

Lastly, the reflection across the y-axis is:

$(x,y) \to (-x,y)$

So, we have:

$(-x,y) \to (x,y)$

So, the overall transformation is:

$(x,y) \to (x,y)$

Notice that, the original and final coordinates are the same.

This means that:

Reflections (a) y=x, x-axis, y=x, y-axis would carry the hexagon onto itself