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suter [353]
3 years ago
6

Commute times in the U.S. are heavily skewed to the right. We select a random sample of 500 people from the 2000 U.S. Census who

reported a non-zero commute time. In this sample the mean commute time is 27.6 minutes with a standard deviation of 19.6 minutes. Are researchers able to conclude from this data that the mean commute time in the U.S. is less than half an hour? Conduct a hypothesis test at the 5% level of significance using StatCrunch (directions) or calculating T and using the T-Distribution Calculator above. Based on your hypothesis test, what can we conclude?
Mathematics
1 answer:
tresset_1 [31]3 years ago
5 0

Answer:

<em>|t|  =  2.739 > 1.972 at 0.05 level of significance</em>

<em>Null hypothesis is rejected  at 0.05 level of significance</em>

<em>The researchers able to conclude from this data that the mean commute time in the U.S. is less than half an hour</em>

<u>Step-by-step explanation</u>:

<u>Step(i)</u>:-

Given sample size n = 500

Given data

<em>mean of the sample x⁻ = 27.6 minutes</em>

<em>Standard deviation of the sample (S) =  19.6 minutes</em>

<em>Mean of the Population 'μ' = half an hour or 30 minutes</em>

<em>Level of significance ∝ =0.05</em>

t₀.₀₅ = 1.972

<u><em>Step(ii):</em></u>-

<u><em>Null hypothesis :H₀</em></u>: <em>μ= 30</em>

<u><em>Alternative Hypothesis :H₁:</em></u> <em>μ < 30</em>

Test statistic

    t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }

   t = \frac{27.6 -30}{\frac{19.6}{\sqrt{500} } }

 t = - 2.739

|t| = |-2.739| = 2.739

<u><em>Final answer</em></u>:-

<em>|t|  =  2.739 > 1.972 at 0.05 level of significance</em>

<em>Null hypothesis is rejected  at 0.05 level of significance</em>

<em>The researchers able to conclude from this data that the mean commute time in the U.S. is less than half an hour</em>

<em></em>

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