Question:
Solution:
Let the following equation:
![\sqrt[]{12-x}=\text{ x}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B12-x%7D%3D%5Ctext%7B%20x%7D)
this is equivalent to:
![(\sqrt[]{12-x})^2=x^2](https://tex.z-dn.net/?f=%28%5Csqrt%5B%5D%7B12-x%7D%29%5E2%3Dx%5E2)
this is equivalent to:

this is equivalent to:

thus, we can conclude that
x= 3.
Answer:
1/6
Step-by-step explanation:
(3 1/3)/20=(10/3)×(1/20)=10/60=1/6
Answer:
47/30
Step-by-step explanation:
2.35 * 2/3 =
= 2 35/100 * 2/3
= 2 7/20 * 2/3
= 47/20 * 2/3
= 94/60
= 47/30
I’m not positive but i think it’s 36x^2 -1