Answer:
Vel_jet_r = (464.645 mph) North + (35.35 mph) East
||Vel_jet_r|| = 465.993 mph
Step-by-step explanation:
We need to decompose the velocity of the wind into a component that can be added (or subtracted from the velocity of the jet)
The velocity of the jet
500 mph North
Velocity of the wind
50 mph SouthEast = 50 cos(45) East + 50 sin (45) South
South = - North
Vel_ wind = 50 cos(45) mph East - 50 sin (45) mph North
Vel _wind = 35.35 mph East - 35.35 mph North
This means that the resulting velocity of the jet is equal to
Vel_jet_r = (500 mph - 35.35 mph) North + 35.35 mph East
Vel_jet_r = (464.645 mph) North + (35.35 mph) East
An the jet has a magnitude velocity of
||Vel_jet_r|| = sqrt ((464.645 mph)^2 + (35.35 mph)^2)
||Vel_jet_r|| = 465.993 mph
Answer:
sinB= 3/5, tanA=4/3, cosB=4/5
Step-by-step explanation:
Answer:
y=3(x+1)^2+7
Step-by-step explanation:
Answer:
63.72 ft^2
128 cm^2
Step-by-step explanation:
5. The area of a triangle is
A = 1/2 bh where b is the base and h is the height
A = 1/2(21.6) * (5.9)
= 63.72 ft^2
6. The scale factor is 20/15 = 4/3
When we find area is the scale factor is squares
(4/3) ^2 = 16/9
Taking the ratio of the areas
A big trap
------------------- = scale factor squared
A little trap
A big trap 16
-------------- = ------
72 9
Using cross products
9A = 16*72
9A = 1152
Divide each side by 9
A = 1152/9
A =128
The area of the large trapezoid is 128 cm^2
