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morpeh [17]
3 years ago
15

3(3 - 8x) - 1 = -6x - 28

Mathematics
2 answers:
Wewaii [24]3 years ago
6 0

Answer:

x=2

Step-by-step explanation:

3(3 - 8x) - 1 = -6x - 28

Distribute

9 -24x -1 = -6x -28

Combine like terms

8 -24x = -6x -28

Add 24x to each side

8-24x+24x = -6x-28+24x

8 = 18x-28

Add 28 to each side

8+28 = 18x-28+28

36 = 18x

Divide each side by 18

36/18 = 18x/18

2 =x

Llana [10]3 years ago
5 0

Answer:

Step-by-step explanation:

3(3-8x)-1=-6x - 28

(3×3)-(3×8x)-1=-6x -28

6-3×8x-1=-6x -28

6-3-1×8x=-6x -28

2×8x=-6x -28

+6x +6x

2×8x+6x=-28

2×14x=-28

-2 -2

14x=-28 -2

14x=-30

÷14 ÷14

x=-30÷14

x=-2.15

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Show work please<br> \sqrt(x+12)-\sqrt(2x+1)=1
Nesterboy [21]

Answer:

x=4

Step-by-step explanation:

Given \displaystyle\\\sqrt{x+12}-\sqrt{2x+1}=1, start by squaring both sides to work towards isolating x:

\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2

Recall (a-b)^2=a^2-2ab+b^2 and \sqrt{a}\cdot \sqrt{b}=\sqrt{a\cdot b}:

\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2\\\implies x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1

Isolate the radical:

\displaystyle\\x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1\\\implies -2\sqrt{(x+12)(2x+1)}=-3x-12\\\implies \sqrt{(x+12)(2x+1)}=\frac{-3x-12}{-2}

Square both sides:

\displaystyle\\(x+12)(2x+1)=\left(\frac{-3x-12}{-2}\right)^2

Expand using FOIL and (a+b)^2=a^2+2ab+b^2:

\displaystyle\\2x^2+25x+12=\frac{9}{4}x^2+18x+36

Move everything to one side to get a quadratic:

\displaystyle-\frac{1}{4}x^2+7x-24=0

Solving using the quadratic formula:

A quadratic in ax^2+bx+c has real solutions \displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}. In \displaystyle-\frac{1}{4}x^2+7x-24, assign values:

\displaystyle \\a=-\frac{1}{4}\\b=7\\c=-24

Solving yields:

\displaystyle\\x=\frac{-7\pm \sqrt{7^2-4\left(-\frac{1}{4}\right)\left(-24\right)}}{2\left(-\frac{1}{4}\right)}\\\\x=\frac{-7\pm \sqrt{25}}{-\frac{1}{2}}\\\\\begin{cases}x=\frac{-7+5}{-0.5}=\frac{-2}{-0.5}=\boxed{4}\\x=\frac{-7-5}{-0.5}=\frac{-12}{-0.5}=24 \:(\text{Extraneous})\end{cases}

Only x=4 works when plugged in the original equation. Therefore, x=24 is extraneous and the only solution is \boxed{x=4}

4 0
2 years ago
Consider the function f(x)=x3+3x2â51x+91. What is the remainder if f(x) is divided by (x+9)? Do not include (x+9) in your answer
makkiz [27]

Answer:

The remainder is 64

Step-by-step explanation:

Consider the function f(x)=x^3+3x^2-51x+91

Use synthetic division to divide by x+9

x+9=0, x=-9

divide the given f(x) by -9 using synthetic division

-9               1           3       -51       91

                  0          -9     54        -27              

         --------------------------------------------------

                  1           -6      3         64

The remainder is 64

                 

         

5 0
3 years ago
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mash [69]

Answer:

x = -10; x = 7  

Step-by-step explanation:

|2x + 3| - 6 =11

Add 6 to each side.

|2x + 3| = 17

Apply the absolute rule: If |x| = a, then x = a or x = -a.

(1) 2x + 3 = 17                    (2) 2x + 3 = -17

Subtract 3 from each side

         2x = 14                                 2x = -20

Divide each side by 2

          x = 7                                   x = -10

<em>Check: </em>

(1) |2(7) + 3| - 6 = 11                     (2) |2(-10) + 3| - 6 = 11

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                    11 = 11                                              11 = 11

7 0
3 years ago
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jonny [76]

Answer:

10%

Step-by-step explanation:

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