1(x-1)/2-1(3-X)/4=2/1. X-1/2-3+x/4=2/1. Find common denominator. 2x-2-3+x=8. 2x+x-5=8 3x=8+5. X=13/3.
Well you need first 1 2/4 of a yard. Then you will need 5/6 of a yard. But first you need to put them together. So we need to find the common denominator. Six and four both share which multiple? Twelve. So let's rewrite that. You need 1 6/12 yards + 10/12 yards of wrapping paper. But before we do anything else we need to fix the mixed number. 1 6/12 isn't as easy to add ad 18/12 is. So 18/12 + 10/12 = 28/12
That can simplify as well. Now it's 14/6 which is equivalent to the fraction we had before. But it can also go down to 2 2/6. Now we can simplify it even further. By dividing it by two we can get 2 1/3. These are the measurements we need. So you would need how many thirds? Seven. (2 1/3 is seven thirds) This is your final answer.
You would need to have seven peices of wrapping paper cut to wrap both gift boxes.
Hypotenuse = 5√6
Let the length of each leg be x, since it is Isosceles .
x² + x² = (5√6)²
2x² = (5 * 5 * √6 * √6)
2x² = 150
x² = 150/2
x² = 75
x = √75
x = √(25 * 3)
x = √25 * √3
x = 5√3
